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lord [1]
2 years ago
12

The bowling ball is whizzing down the bowling lane at 4 m/s. If the mass of the bowling ball is 7 kg, what is its kinetic energy

?
Physics
2 answers:
luda_lava [24]2 years ago
5 0

Answer:

56J

Explanation:

Formula to calculate kinetic energy:

K=(1/2)*m*v^{2}  ,equation (1)

K: It's the kinetic energy in Joules (J)

m: body mass in kilograms (kg)

v: body speed in meters / second (m / s)

Known information:

m = 7kg

v = 4 m / s

We replace the known information in  the equation 1:

K=( 1/2)*7*4^{2}

K=56 kg*m^{2} /s^{2} = 14 Newton*metro

K=56J

Lisa [10]2 years ago
3 0
Kinetic Energy = 1/2xmassx(velocity)^2
Input values;
K.E=1/2x7kgx(4m/s)^2
K.E.=56J
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Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant sp
Savatey [412]

km x h = km/h

First trial: 6 x 1 = 6km/h

Second trial: 9 x 2 = 18km/h

6 + 18 = <u>24km/h</u> (Total)

Or

6 + 9 = 15 km

2 + 1 = 3h

15 + 3 = 18

15 x 2 = 30

3 x 2 = 6

30 - 6 = <u>24km/h</u>

8 0
2 years ago
A small box of mass m1 is sitting on a board of mass m2 and length L (Figure 1) . The board rests on a frictionless horizontal s
chubhunter [2.5K]

Explanation:

Whole system will accelerate under the action of applied force. The box will experience the force against the friction and when this force exceeds then the box will move. so

Ff = μs×m1×g

m1×a = μs×m1×g

a = μs×g

The applied force is given by

F = (m1 + m2)×a so

F = μs×g×(m1+m2)

3 0
1 year ago
A block of mass 2.00 kg is initially at rest at x=0 on a slippery horizontal surface for which there is no friction. Starting at
Allisa [31]

Answer:

   x = 1,185 m ,     t = 4/3 s ,  F = - 4 N

Explanation:

For this exercise we use Newton's second law

         F = m a = m dv /dt

        β - α t = m dv / dt

        dv = (β – α t) dt

     

We integrate

        v = β t - ½ α t²

We evaluate between the lower limits v = v₀ for t = 0 and the upper limit v = v for t = t

       v-v₀ = β t - ½ α t²

the farthest point of the body is when v = v₀ = 0

  0 = β t - ½ α t²

  t = 2 β / α

  t = 2 4/6

  t = 4/3 s

Let's find the distance at this time

   v = dx / dt

   dx / dt = v₀ + β t - ½ α t2

   dx = (v₀ + β t - ½ α t2) dt

We integrate

   x = v₀ t + ½ β t - ½ 1/3 α t³

   x = v₀ 4/3 + ½ 4 (4/3)² - 1/6 6 (4/3)³

The body comes out of rest

    x = 3.5556 - 2.37

    x = 1,185 m

The value of force is

    F = β - α t

    F = 4 - 6 4/3

   F = - 4 N

8 0
1 year ago
Two flat conductors are placed with their inner faces separated by 6.0 mm. If the surface charge density on one of the inner fac
dangina [55]

Explanation:

Relation between electric field and charge density is as follows.

           E = \frac{\sigma}{2 \epsilon}

where,    \sigma = charge density

              \epsilon = permittivity of free space = 8.85 \times 10^{-12}

So,  E_{\text{outside}} = 0

      E_{inside} = \frac{+\sigma}{2 \epsilon} - \frac{-\sigma}{2 \epsilon}

or,     E_{inside} = \frac{\sigma}{\epsilon}

Now, formula to calculate the potential difference of two conductors is as follows.

         V_{1} - V_{2} = \frac{\sigma \times d}{\epsilon}

It is given that,

           d = 6.0 mm = 6 \times 10^{-3} m

        \sigma = 40 \times 10^{-12} C/m^{2}

Hence, we will calculate the magnitude of the electric potential differences between the two conductors as follows.

        V_{1} - V_{2} = \frac{\sigma \times d}{\epsilon}

                     = \frac{40 \times 10^{-12} \times 6 \times 10^{-3}}{8.85 \times 10^{-12}}      

                     = 0.0271 volts

thus, we can conclude that value of the magnitude of the electric potential differences between the two conductors is 0.0271 volts.

7 0
2 years ago
Quickly spinning the handle of a hand generator, Kristina is able to light three bulbs in a circuit. When she spins the generato
erastova [34]

Answer:

  • <u><em>Voltage is too low</em></u>

Explanation:

<em>Generators</em> produce a potential difference (voltage) by <em>spinning </em>a coil of wire in a magnetic field by induction.

The  produced voltage is proportional to the relative speed of the coil wire with respect to the magnetic field.

Hence, for a given generator, the higher the speed the higher the potential difference.

Therefore, it is concluded immediately that when Kristina spins the generator slowly, less potential difference (voltage) is generated.

Also, you must know that the brightness of the bulbs varies with the current: the higher the current, the brigther the bulbs.

On the other hand, the basic realtion between voltage (V), resistance (R), and current I) is given by Ohm's law: V = R × I. This is, voltage and current are proportional.

Since the generator is producting less voltage, for the same bulbs (which are resistors) , the current will be lower too. And, as stated, lower current means lower brightness, which explains why when Kristina spins the generator slowly, the bulbs are very dim.

5 0
2 years ago
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