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geniusboy [140]
2 years ago
10

A book is moved once around the edge of a tabletop with dimensions 1.75 m à 2.25 m. If the book ends up at its initial position,

what is its displacement? If it completes its motion in 23 s, what is its average velocity? What is its average speed?
Physics
1 answer:
uysha [10]2 years ago
6 0

Explanation:

The dimension of the book is 1.75 m × 2.25 m. If the book ends up at its initial position. The displacement of the book is equal to zero as the object reaches to its initial position.

If it completes its motion in 23 s, t = 23 s

Total displacement of the book is equal to its perimeter. It is given by :

d=2(1.75+2.25)=8\ m

The net displacement divided by total time taken is called the average velocity of an object. Here, the displacement is 0. So, average velocity is 0.

The average speed of an object is given by :

v=\dfrac{d}{t}

v=\dfrac{8\ m}{23\ s}

v = 0.347 m/s

So, the average speed of the book is 0.347 m/s. Hence, this is the required solution.

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A farm hand does 972 J of work pulling an empty hay wagon along level ground with a force of 310 N [23° below the horizontal]. T
irina1246 [14]

Answer:

Option d)

Solution:

As per the question:

Work done by farm hand, W_{FH} = 972J

Force exerted, F' = 310 N

Angle, \theta = 23^{\circ}

Now,

The component of force acting horizontally is F'cos\theta

Also, we know that the work done is the dot or scalar product of force and the displacement in the direction of the force acting on an object.

Thus

W_{FH} = \vec{F'}.\vec{d}

972 = 310\times dcos23^{\circ}

d = 3.406 m = 3.4 m

3 0
2 years ago
A mouse runs along a baseboard in your house. The mouse's position as a function of time is given by x(t)=pt2+qt, with p = 0.36
AlexFokin [52]

Answer:

0.60 m/s

Explanation:

The average velocity from t = a to t = b is:

v_avg = (x(b) − x(a)) / (b − a)

Given that x(t) = 0.36t² − 1.20t, and the time is from 1.0 to 4.0:

v_avg = (x(4.0) − x(1.0)) / (4.0 − 1.0)

v_avg = [(0.36(4.0)² − 1.20(4.0)) − (0.36(1.0)² − 1.20(1.0))] / 3.0

v_avg = [(5.76 − 4.8) − (0.36 − 1.20)] / 3.0

v_avg = [0.96 − (-0.84)] / 3.0

v_avg = 0.60

The average speed is 0.60 m/s.

5 0
2 years ago
Biologists have studied the running ability of the northern quoll, a marsupial indigenous to Australia. In one set of experiment
Dominik [7]

Answer:

\mu=0.74            

Explanation:

It is given that,

Speed of one quoll around a curve, v = 3.2 m/s (maximum speed)

Radius of the curve, r = 1.4 m

On the curve, the centripetal force is balanced by the frictional force such that the coefficient of frictional is given by :

\mu=\dfrac{v^2}{rg}

\mu=\dfrac{(3.2\ m/s)^2}{1.4\ m\times 9.8\ m/s^2}

\mu=0.74

So, the coefficient of static friction between the quoll's feet and the ground in this trial is 0.74. Hence, this is the required solution.

6 0
2 years ago
Read 2 more answers
Keisha looks out the window from a tall building at her friend Monique standing on the ground, 8.3 m away from the side of the b
Salsk061 [2.6K]

Answer:

Explanation:

GIVEN DATA:

Distance between keisha and her friend 8.3 m

angle made by keisha toside building 30 degree

height of her friend monique is 1.5 m

from the figure

\Delta ACB

tan 30 = \frac{8.3}{h}

h= \frac{8.3}{tan 30} = 14.376 m

therefore

height of keisha is = h  + 1.5 m

                               = 14.376 + 1.5

= 15.876 \simeq 16 m

therefore option c is correct

5 0
2 years ago
Why are we able to use nuclear energy for practical purposes? The reactions are controlled to regulate energy output. The reacti
musickatia [10]

Answer: The reactions are controlled to regulate energy output

Explanation:

Nuclear energy is produced when either two nuclei fuse to produce larger nucleus or a bigger nuclei splits into two smaller nucleus.

Uranium easily splits to produce nuclear energy. The reactions are controlled and energy output can be regulated. Nuclear energy in abundant yet controlled amount is available. Nuclear energy is mostly used in steam turbines to produce electricity.  

5 0
2 years ago
Read 2 more answers
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