If John mows 11.5 meters of lawn from east

First find ∮RB⃗ ⋅dl⃗ , the line integral of B⃗ around a loop of radius R located just outside the left capacitor plate. This can

Allisa [31]

Answer:

the expression of current in the loop enclosed to the left of the capacitor plate is

$I(t) = \frac{1}{\mu_0}\int B. dL$

Explanation:

As we know by Ampere's law that line integral of magnetic field around a closed loop is proportional to the current enclosed in the path

So we will have

$\int B. dL = \mu_0 I(t)$

so we have

$I(t) = \frac{1}{\mu_0}\int B. dL$

so above is the expression of current in the loop enclosed to the left of the capacitor plate

5 0

2 years ago

The diagram shows the electric field due to point charge Q. Which statements are correct? Check all that apply.

Bess [88]

Answer:

The correct statements are:

A. The electric field is nonuniform.

D. Charge Q is positive.

E. If charge A moves toward charge Q, it must be a negative charge

Explanation:

The answer choices are:

A. The electric field is nonuniform.

B. The electric field is uniform.

C. Charge Q is negative.

D. Charge Q is positive.

E. If charge A moves toward charge Q, it must be a negative charge.

F. If charge A moves toward charge Q, it must be a positive charge.

<h2>Solution</h2>

The electric field is the electrostatic force per unit of charge,

$\vec E=\dfrac{\vec F}{Q}$

around around a charge, where another charge would experience the electrostatic force.

The electric field lines are shown in a diagram with arrows ditributed radially away from a positive charge and radially toward a negative charge.

Since the arrows are away from Q, Q is a positive charge: statement D.

Since the size of the arrows decreases as you move away from Q the stregth of the field is not uniform: statement A.

Since the charge Q is positive, a negative charge would be attracted toward it: statement E.

4 0

2 years ago

The discovery and characterization of cathode rays was important in the development of the atomic theory because

Viefleur [7K]

Answer:

All matter contained electrons

Explanation:

The discovery and characterization of cathode ray suggested that it was a subatomic particle and cathode ray ( electron) was the first discovered. It immensely became the strong explanatory tool for chemical bond. This can be attributed to the the ease with which electron move from one atom to the other.

3 0

2 years ago

A solar-powered car has a kinetic energy of 110250J. Its mass is 180kg. Work out how fast the car is travelling.

vfiekz [6]

Answer:

Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

$K.E = \frac{1}{2}mv^{2}$

$v^{2}=\frac{2K.E}{m}$

$v =\sqrt{\frac{2K.E}{m} }$

$v = \sqrt{\frac{(2)(110250)}{180} }$

v = 35 m/s

7 0

2 years ago

Read 2 more answers

Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50

defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0

2 years ago