Answer:
to the right.
to in the upwards direction.
Explanation:
In order to solve this problem, we must first start by drawing a diagram of the situation. (See attached diagram).
So, remember that a force is determined by multiplying the mass of the parcticle by its acceleration:
F=ma
so in order to find the components of the force, we need to start by finding its acceleration.
Acceleration is found by using the following formula:

so we can subtract the two vectors, like this:

which yields:

or:

so now I can find the components of the force:

which yields:
F=(2.31i+2.1j)N
so the components of the force are:
to the right.
to in the upwards direction.
Answer:
W
Explanation:
= Temperature of the room = 22.0 °C = 22 + 273 = 295 K
= Temperature of the skin = 33.0 °C = 33 + 273 = 306 K
= Surface area = 1.50 m²
= emissivity = 0.97
= Stefan's constant = 5.67 x 10⁻⁸ Wm⁻² K⁻⁴
Rate of heat transfer is given as


W
Answer:
h=20.66m
Explanation:
First we need the speed when the cord starts stretching:


This will be our initial speed for a balance of energy.
By conservation of energy:

Where
is your height at its maximum elongation
is the height of the bridge
is the length of the unstretched bungee cord

Solving for h:
and
Since 99m is higher than the initial height of 79m, we discard that value.
So, the final height above water is 20.66m
Answer:
a) f = 615.2 Hz b) f = 307.6 Hz
Explanation:
The speed in a wave on a string is
v = √ T / μ
also the speed a wave must meet the relationship
v = λ f
Let's use these expressions in our problem, for the initial conditions
v = √ T₀ /μ
√ (T₀/ μ) = λ₀ f₀
now it indicates that the tension is doubled
T = 2T₀
√ (T /μ) = λ f
√( 2To /μ) = λ f
√2 √ T₀ /μ = λ f
we substitute
√2 (λ₀ f₀) = λ f
if we suppose that in both cases the string is in the same fundamental harmonic, this means that the wavelength only depends on the length of the string, which does not change
λ₀ = λ
f = f₀ √2
f = 435 √ 2
f = 615.2 Hz
b) The tension is cut in half
T = T₀ / 2
√ (T₀ / 2muy) = f = λ f
√ (T₀ / μ) 1 /√2 = λ f
fo / √2 = f
f = 435 / √2
f = 307.6 Hz
Traslate
La velocidad en una onda en una cuerda es
v = √ T/μ
ademas la velocidad una onda debe cumplir la relación
v= λ f
Usemos estas expresión en nuestro problema, para las condiciones iniciales
v= √ To/μ
√ ( T₀/μ) = λ₀ f₀
ahora nos indica que la tensión se duplica
T = 2T₀
√ ( T/μ) = λf
√ ) 2T₀/μ = λ f
√ 2 √ T₀/μ = λ f
substituimos
√2 ( λ₀ f₀) = λ f
si suponemos que en los dos caso la cuerda este en el mismo armónico fundamental, esto es que la longitud de onda unicamente depende de la longitud de la cuerda, la cual no cambia
λ₀ = λ
f = f₀ √2
f = 435 √2
f = 615,2 Hz
b) La tension se reduce a la mitad
T = T₀/2
RA ( T₀/2μ) = λ f
Ra(T₀/μ) 1/ra 2 = λ f
fo /√ 2 = f
f = 435/√2
f = 307,6 Hz
Answer:
The magnitudes of the net magnetic fields at points A and B is 2.66 x
T
Explanation:
Given information :
The current of each wires, I = 4.7 A
dH = 0.19 m
dV = 0.41 m
The magnetic of straight-current wire :
B= μ
I/2πr
where
B = magnetic field (T)
μ
= 1.26 x
(N/
)
I = Current (A)
r = radius (m)
the magnetic field at points A and B is the same because both of wires have the same distance. Based on the right-hand rule, the net magnetic field of A and B is canceled each other (or substracted). Thus,
BH = μ
I/2πr
= (1.26 x
)(4.7)/(2π)(0.19)
= 4.96 x
T
BV = μ
I/2πr
= (1.26 x
)(4.7)/(2π)(0.41)
= 2.3 x
T
hence,
the net magnetic field = BH - BV
= 4.96 x
- 2.3 x 
= 2.66 x
T