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2 years ago

Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity?

Physics

2 answers:

saul85 [17]2 years ago

8 0

Average velocity = (displacement)/(time)

Since Walt ran in a straight line, the magnitude of his displacement

was equal to the distance he ran = 5 km.

(displacement) / (time) = (5 km east) / (25 min)

Average velocity = 0.2 km/minute east

That's also equal to 12 km/hour east

storchak [24]2 years ago

7 0

1km per 5 mins
PLEASE VERIFY WITH SOMEONE I MAY BE INCORRECT

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Answer:

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Once we have the initial speed, we can isolate the final speed from following equation:

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Then we can calculate the aceleration where the car stops 0.5 m before striking the tree.

To do that, we replace 62 m in the first formula, as follows:

$x=V_{0} *t+\frac{1}{2} *a*(t^{2} )\\62m=25.953\frac{m}{s}*4.15s+\frac{1}{2} *-a\frac{m}{s^{2} } *(4.15^{2} )\\a=-5.19\frac{m}{s^{2} }$

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Julli [10]

The question above can be answered through using the concept of Conservation of Momentum which may be expressed as,
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