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r-ruslan [8.4K]
2 years ago
5

Elements in group 2 are all called alkaline earth metals. What is most similar about the alkaline earth metals? how many protons

and neutrons they have which chemical properties they have how many total electrons they have which period they are most often found in
Physics
2 answers:
Rom4ik [11]2 years ago
4 0

Elements in group 2 are called alkaline earth metals, the most similarity about the alkaline metals is which chemical properties they have.

<h2>Further Explanation </h2><h3>Periodic table  </h3>
  • Periodic table is a table that contains elements arranged in columns called groups and rows called periods.
  • Elements are arranged based on physical and chemical properties such that elements in the same group will have similar physical and chemical properties.  
<h3>Chemical families  </h3>
  • Based on the chemical properties elements belong to a family of elements sharing similar chemical or physical characteristics.
  • Examples of common chemical families include; alkali metals, alkaline-earth metals, halogens and noble gases among others.
<h3>Alkaline-earth metals  </h3>
  • These are elements that are found in group 2 of the periodic table. Alkaline-earth metals include, Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium.  

Properties  of Alkaline-earth metals

  • Alkaline earth metals have a valence of two since they form ions by losing two electrons from their outermost energy levels.
  • Unlike the Alkali metals, the earth metals have a smaller atom size and are not as reactive compared to alkali metals.
  • Alkaline-earth metals are highly metallic and are good conductors of electricity.  
  • They react with water and steam to form metal hydroxide and metal oxides respectively  
  • They react with air to form metal oxides  
  • Reactivity of alkaline metals depends on the ease of losing electrons, thus the reactivity increases down the group as the number of energy levels increases.
  • Additionally, alkaline-earth metals have low electronegativities and low electron affinities  

Keywords: Chemical families, alkaline-earth metals, reactivity  

<h3>Learn more about:  </h3>
  • Chemical families: brainly.com/question/1358941
  • Alkaline-earth metals: brainly.com/question/8498732
  • Properties of alkaline-earth metals: brainly.com/question/11116789
  • Reactivity of metals: brainly.com/question/7101478

Level: High school  

Subject: Chemistry  

Topic: Periodic table and chemical families  

Sub-topic: Alkaline-earth metals  

Jlenok [28]2 years ago
4 0

Answer:

which chemical properties they have

Explanation:

Guest
1 year ago
edge 2021
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Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

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Force = 615 N

Time(t) = 1 s

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Force = mass x acceleration

Thus;

615 = 110 × acceleration

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Now, using Newton's first law of motion, we can find acceleration (a). Thus;

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Answer:

The flux through the surface of the cube is 2.314\ Nm^{2}/C

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As per the question:

Edge of the cube, a = 8.0 cm = 8.0\times 10^{- 2}\ m

Volume Charge density, \rho_{v} = 40 nC/m^{3} = 40\times {- 9}\ C/m^{3}

Now,

To calculate the electric flux:

\phi = \frac{q}{\epsilon_{o}}                                                      (1)

where

\phi = electric flux

\epsilon_{o} = 8.85\times 10^{- 12}\ F/m = permittivity of free space  

Volume Charge density for the given case is given by the formula:

\rho_{v} = \frac{Total\ charge, q}{Volume of cube, V}                  (2)

Volume of cube, V = a^{3}

Thus

V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}

Thus from eqn (2), the total charge is given by:

q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}

q = 2.048\times 10^{-11}\ F = 20.48\ pF

Now, substitute the value of 'q' in eqn (1):

\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C

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A cylindrical rod of steel (E = 207 GPa, 30 × 10 6 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a
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We know that young's modulus E=\frac{stress}{strain}

So 207\times 10^9=\frac{stress}{7.6\times 10^{-4}}

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A, B, and E

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