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Natali5045456 [20]
2 years ago
9

Debbie places two shopping carts in a cart Corral. she pushes the first cart, which then pushes a second cart. what force is bei

ng exerted?
Physics
1 answer:
Bingel [31]2 years ago
6 0

When Debbie pushes the first cart she is using an applied force. An applied force is created when someone or something pushes another thing using, of course, an applied force. Now, when the second cart is being pushed by the first cart, this is also an applied force. You can tell because the first cart is being pushed using forced and this causes the second cart to be pushed using some of the force that is being transmitted to the first cart.


Debbie exerts applied force on the first cart. The first cart exert applied force on the second cart.



- Marlon Nunez

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As the external magnetic field decreases, an induced current flows in the coil. what is the direction of the induced magnetic fi
GrogVix [38]
As the external magnetic field decreases, an induced current flows in the coil. The direction of the induced magnetic field would be pointing to the screen. The flux through the coil is said to decrease. In order to counter this change, the coil would generate or produce a magnetic field that is induced that would be pointing to the same direction as the external field that is flowing which is into the the screen. This is according to Lenz's law or the right hand rule. It states that an induced current in a circuit that is due to the change or motion in   magnetic field should be directed opposing to the change in the flux.
4 0
2 years ago
A material that has a fracture toughness of 33 MPa.m0.5 is to be made into a large panel that is 2000 mm long by 250 mm wide and
scoray [572]

Answer:

F_{allow} = 208.15kN

Explanation:

The word 'nun' for thickness, I will interpret in international units, that is, mm.

We will begin by defining the intensity factor for the steel through the relationship between the safety factor and the fracture resistance of the panel.

The equation is,

K_{allow} =\frac{K_c}{N}

We know that K_c is 33Mpa*m^{0.5} and our Safety factor is 2,

K_{allow} = \frac{33Mpa*m^{0.5}}{2} = 16.5MPa.m^{0.5}

Now we will need to find the average width of both the crack and the panel, these values are found by multiplying the measured values given by 1/2

<em>For the crack;</em>

\alpha = 0.5*L_c = 0.5*4mm = 2mm

<em>For the panel</em>

\gamma = 0.5*W = 0.5*250mm = 125mm

To find now the goemetry factor we need to use this equation

\beta = \sqrt{sec(\frac{\pi\alpha}{2\gamma})}\\\beta = \sqrt{sec(\frac{2\pi}{2*125mm})}\\\beta = 1

That allow us to determine the allowable nominal stress,

\sigma_{allow} = \frac{K_{allow}}{\beta \sqrt{\pi\alpha}}

\sigma_{allow} = \frac{16.5}{1*\sqrt{2*10^{-3} \pi}}

\sigma_{allow} = 208.15Mpa

So to get the force we need only to apply the equation of Force, where

F_{allow}=\sigma_{allow}*L_c*W

F_{allow} = 208.15*250*4

F_{allow} = 208.15kN

That is the maximum tensile load before a catastrophic failure.

4 0
2 years ago
What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always making an angle θ fro
Rainbow [258]

Answer:

v = √(Lsinθ tanθ)

Explanation:

From the diagram attached,

v = the tangential speed.

r = the radius of the horizontal circle.

T = tension in the string.

θ =  the angle that the string makes with the vertical

m =  Bob's mass  (mg = the weight)

F =  centripetal force

L = the length of the string

From geometry,

r = Lsin θ

Thus, the centripetal acceleration is given as;

a = v²/r = v²/Lsin θ

Force = mass x acceleration

Thus,

Centripetal force = mv²/Lsin θ

Let's balance the vertical forces to obtain,

T cosθ - mg = 0

Thus, T cosθ = mg - - - - (eq1)

Similarly, let's balance the horizontal forces to obtain;

T sinθ = F = mv²/Lsin θ

So, T sinθ = mv²/Lsin θ - - - - (eq2)

Let's divide eq 2 by eq 1 to get;

Tsinθ/Tcosθ = (mv²/Lsin θ)/mg

tanθ = gv²/Lsinθ

Thus, v² =  Lsinθ tanθ

v = √(Lsinθ tanθ)

4 0
2 years ago
A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta
-Dominant- [34]

The car would go from  zero to 58.0 mph in 2.6 sec.

Since the force on the car is constant, therefore the acceleration of the car would also be constant.

Now for constant acceleration we can use the equation of motion

Using first equation of motion to calculate the acceleration of the car

v=u+at

29=0+a×1.30       ...... Eq. (1)

Again using the first equation of motion

58=0+a*t             ....... Eq. (2)

Dividing eq. (2) with equation 1

t=2×1.3

t=2.6 sec

7 0
2 years ago
Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long. How long is the ot
s344n2d4d5 [400]

Answer:

The length of the longer pipe is L = 2.30 m

Explanation:

Given that:

Two open organ pipes, sounding together, produce a beat frequency of 8.0 Hz . The shorter one is 2.08 m long.

How long is the other pipe?

From above;

The formula for the frequency of open ended pipes can be expressed as:

f = \dfrac{nv}{2L}

where n = 1 ( since half wavelength exist between those two pipes)

v = 343 m/s  and L = 2.08 m

Thus, the shorter pipe produces a frequency of :

f = \dfrac{1*343}{2*2.08}

f = \dfrac{343}{4.16}

f =82.45 \ Hz

Also; we know that the beat frequency was given as 8.0 Hz

Then,

The lower frequency of the longer pipe = ( 82.45 - 8.0 )Hz

The lower frequency of the longer pipe = 74.45 Hz

Finally;

From the above equation; make Length L the subject of the formula. Then,

The length of the longer pipe is L = \dfrac{nv}{2f}

The length of the longer pipe is L = \dfrac{1*343}{2*74.45}

The length of the longer pipe is L = \dfrac{343}{148.9}

The length of the longer pipe is L = 2.30 m

6 0
2 years ago
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