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2 years ago

Which description best explains a molecular bonding?

Physics

1 answer:

poizon [28]2 years ago

3 0

Explanation:

Which description best explains a molecular bonding? Shares electrons

A covalent bond is also known also known as molecular bonding because sharing of electrons occur between two or more atoms.

Molecular bonds are formed between two or more atoms having zero or very small electronegativity difference between them.
This bond type exists between molecules of non-metals.
Each of the atom tends to share the valence electrons in their outer energy levels to be able to mimic the noble gas structure.
This bond type results in formation of molecules.

Learn more:

Covalent bonds brainly.com/question/6029316

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Isotopes of the same elements always have the same Z-number

Isotopes of an element have the same electronic configuration hence they have the same chemical properties.

isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers.
This is due to the differences in the number of neutrons in their various nuclei.

A- number is the mass number or atomic mass number of an atom.

Z-number is the atomic number of an atom

Isotopes have the same atomic number.

Learn more:

Isotopes brainly.com/question/4551913

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Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.

Rutherford performed an experiment that gave that atomic model a significant leap.
He found out most alpha particles passed through the foil while a few of them deflected back.
He proposed that an atom is made up of a small positively charge center where nearly all the mass is concentrated.

Learn more:

Rutherford brainly.com/question/1859083

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Burning paper

A chemical change is one in which a new kind of matter is formed.
Chemical changes are always accompanied by energy changes which can be absorption or evolution.
These processes are not easily reversible.
It involves a change in mass
It requires considerable amount of energy.

When a paper is burnt, it turns to ashes. Ashes cannot be turned back into a paper. This is a chemical change.

Learn more:

Chemical change brainly.com/question/9388643

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It remains the same

When the number of neutrons in an atom increases, the atomic number stays the same.

The atomic number is the number of protons in an atom.
Protons are positively charged particles in the nucleus of an atom.
When the number of neutrons changes, the mass number changes.
Neutrons have no effect on the number of protons in an atom.
They are both sub-atomic particles with electrons

Learn more:

Atomic number brainly.com/question/5425825

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Equal number of protons and electrons

Protons are the positively charged particles in atom. Electrons are the negatively charged particles in an atom.

Every atom is electrically neutral.
Electrical neutrality is achieved when the number of protons and electrons are the same.
In atoms, this number is the same.
If the number differs, such an atom is called an ion.

Learn more:

Cations and anions brainly.com/question/4223679

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11 electrons

In a neutral atom, the number of protons and electrons are the same.

Protons are the positively charged particles in an atom.
Electrons are the negatively charged particles in an atom.
Neutrons do not carry any charges in an atom.
A charged atom is an atom that has lost or gained electrons.
In a neutral atom, the number of protons and electrons are the same.

Learn more:

Cations and anions brainly.com/question/4223679

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Thomson D) Electrons

Rutherford B) Nucleus

Bohr C) Electron energy levels

Schrodinger A) Electron cloud and orbitals

J.J Thomson experimented on gas discharge tubes and this led to the discovery of electrons as a subatomic particle. He called the particles cathode rays.
Ernest Rutherford performed the gold foil experiment that gave the modelling of the atom a significant boost. He found that most of the alpha particles passed through the foil while a few of them deflected back. To explain this, he suggested that an atom is made up of a positively charged center where nearly all the mass is concentrated.
Neil Bohr suggested that the extranuclear space is made up of electrons in specific spherical orbits. Electrons move round the nucleus in certain permissible orbits called energy levels.
Erwin Schrodinger formulated the wave equation for electrons. He suggested that the region of maximum probability of where n electron is located is referred to as an electron cloud or orbital.

Learn more:

Nells Bohr brainly.com/question/4986277

Rutherford brainly.com/question/1859083

#learnwithBrainly

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Alex goes cruising on his dirt bike. He rides 700m north, 300m east, 400 m north, 600m west, 1200m south, 300m east and finally

Bess [88]

Find Displacement and Distance

displacement ...

north is 700+400+100 =1200m n

south=1200m

1200-1200=0

east is 300+300=600m

west is 600m

600-600=0

back at dtart. displ zero

distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m = 3600m

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2 years ago

A 0.242 g sample of potassium is heated in oxygen. The result is 0.292 g of a crystalline compound. What is the formula of this

masha68 [24]

Answer:

Hello there Dude answer is B :D hope it helped mark me brainliest.

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2 years ago

You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t

kati45 [8]

Answer:

The coefficient of kinetic friction $\mu_k = 0.724$

Explanation:

From the question we are told that

The length of the lane is $l = 36.0 \ m$

The speed of the truck is $v = 22.6\ m/s$

Generally from the work-energy theorem we have that

$\Delta KE = N * \mu_k * l$

Here N is the normal force acting on the truck which is mathematically represented as

$\Delta KE$ is the change in kinetic energy which is mathematically represented as

$\Delta KE = \frac{1}{2} * m * v^2$

=> $\Delta KE = 0.5 * m * 22.6^2$

=> $\Delta KE = 255.38m$

$255.38m = m * 9.8 * \mu_k * 36.0$

=> $255.38 = 352.8 * \mu_k$

=> $\mu_k = 0.724$

6 0

2 years ago

The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the cente

kipiarov [429]

Answer:

$I=68.31\times 10^{-6}\ A$

Explanation:

Given that

J(r) = Br

We know that area of small element

dA = 2 π dr

I = J A

dI = J dA

Now by putting the values

dI = B r . 2 π dr

dI= 2π Br² dr

Now by integrating above equation

$\int_{0}^{I}dI= \int_{r_1}^{r_2}2\pi Br^2 dr$

$I={2\pi B}\times \dfrac{r_2^3-r_1^3}{3}$

Given that

B= 2.35 x 10⁵ A/m³

r₁ = 2 mm

r₂ = 2+ 0.0115 mm

r₂ = 2.0115 mm

$I={2\pi B}\times \dfrac{r_2^3-r_1^3}{3}$

By putting the values

$I={2\pi \times 2.35 \times 10^5 }\times \dfrac{(2.0115\times 10^{-3})^3-(2\times 10^{-3})^3}{3}\ A$

$I=68.31\times 10^{-6}\ A$

7 0

2 years ago

Read 2 more answers

Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m

netineya [11]

Answer: $m \frac{d}{dt}v_{(t)}$

Explanation:

In the image attached with this answer are shown the given options from which only one is correct.

The correct expression is:

$m \frac{d}{dt}v_{(t)}$

Because, if we derive velocity $v_{t}$ with respect to time $t$ we will have acceleration $a$ , hence:

$m \frac{d}{dt}v_{(t)}=m.a$

Where $m$ is the mass with units of kilograms ( $kg$ ) and $a$ with units of meter per square seconds $\frac{m}{s}^{2}$ , having as a result $kg\frac{m}{s}^{2}$

The other expressions are incorrect, let’s prove it:

$\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)}$ This result has units of $kg\frac{m}{s}$

$m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m$ This result has units of $kg$

$m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C$ This result has units of $kgm^{2}$ and $C$ is a constant

$m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m$ This result has units of $kg$

$m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m$ This result has units of $kg$

$\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C$ This result has units of $kg \frac{m^{3}}{s^{3}}$ and $C$ is a constant

$m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C$ This result has units of $kg \frac{m^{2}}{s^{4}}$ and $C$ is a constant

$\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0$ because $v_{(x)}$ is a constant in this derivation respect to $t$

$m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C$ This result has units of $kg \frac{m^{2}}{s^{2}}$ and $C$ is a constant

6 0

2 years ago