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andrezito [222]
2 years ago
7

Which statements describe the characteristics of asteroids? Check all that apply. formed 4.6 billion years ago orbit the Sun bey

ond Jupiter range in size from a few feet to more than 500 miles across have a total mass greater than the mass of the moon most are found in the asteroid belt
Physics
2 answers:
choli [55]2 years ago
6 0

Answer:

formed 4.6 billion years ago

orbit the Sun

range in size from a few feet to more than 500 miles across

most are found in the asteroid belt

Explanation:

Asteroids are rocky bodies orbiting the sun. Asteroids are irregular is shape and size. The size varies from few feet to 500 miles across. Majority of the asteroids lie in asteroid belt which lies between the orbits of Mars and Jupiter. These are though to be remains of unformed planet about 4.6 billion years ago due to high gravitational pull of Jupiter. The largest asteroid is Ceres which is also a dwarf planet. The mass of the entire asteroid belt is just 4% the  mass of the moon.

shepuryov [24]2 years ago
5 0

Answer:

hes wrong its actually 1 3 5 on edg 2020

Explanation:

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At room temperature, a typical person loses energy to the surroundings at the rate of 62 W. If this energy loss has to be made u
Alex_Xolod [135]

To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.

The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was

P = \frac{E}{t} \rightarrow E= Energy, t = time

P = 62W = 62 \frac{J}{s}

The rate of energy loss per day would then be,

P = 62\frac{J}{s} (\frac{86400s}{1day})

P = 5356800 \frac{J}{day}

That is to say that Energy in Jules per lost day is 5356800J

By definition we know that 1KCal = 4.184*10^{6}J

In this way the energy in Cal is,

E = 5356800J \frac{1KCal}{4.184*10^{6}J}

E = 1279.694 KCal

The number of kilocalories (food calories) must be 1279.694 KCal

4 0
2 years ago
How many slices of bread did each climber have to eat to compensate for the increase of the gravitational potential energy of th
N76 [4]

Answer:

So No of slices to be consumed by each person = n = 65

Explanation:

Energy released by one slice = E1

E1=10^6\ J

h = 8850 m ; m = 79 kg ,η= 10.5%

We know that potential energy given as

u = m g h

u = 79 x 9.81 x 8850

u=6.8\times 10^6\ J

we know from the defination of efficiency that,  η= E(out)/E(in)

Now amount of PE has to be compensated, In our case, E(out) =u

0.105=\dfrac{E(out)}{E(in)}

0.105=\dfrac{6.8\times 10^6}{E(in)}

E(in)=64.76\times 10^6\ J

Let n be the number of bread slices to be consumed.

n = E(in)/E1

n=\dfrac{64.76\times 10^6}{10^6}

n=64.76

So No of slices to be consumed by each person = n = 65

3 0
2 years ago
You are participating in a NASA traineeship, working with a group planning a new landing on Mars. Your supervisor has come up wi
aivan3 [116]

Answer:

h=17005.8 km

Explanation:

Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass M=6.39\times10^{23} kg at a distance r will be:

F=\frac{GMm}{r^2}

where G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant.

This force is the centripetal force the satellite experiments, so we can write:

F=ma_{cp}=mr\omega^2=mr(\frac{2\pi}{T})^2=\frac{4\pi^2mr}{T^2}

Putting all together:

\frac{GMm}{r^2}=\frac{4\pi^2mr}{T^2}

which means:

r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}

Which for our values is:

r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km

Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km , which leaves us with:

h=r-R=20395.3km-3389.5 km=17005.8 km

6 0
2 years ago
The air surrounding an airplane in flight exerts a drag force that acts opposite to the airplane's motion. When an Airbus A380 i
Rainbow [258]

Answer:

4.32\cdot 10^5 hp, 3.22\cdot 10^8 W

Explanation:

The jet is flying at constant velocity: this means that its acceleration is zero, so the net force acting on the jet is also zero.

Therefore, we can write:

4F_T - F_d = 0

where

F_T = 322,000 N is the thrust force generated by each engine of the jet

F_d is the drag force

Solving for Fd,

F_d = 4 F_T = 4(322,000)=1.288\cdot 10^6 N

The velocity of the jet is

v=250 m/s

So, the rate at which the drag force does work (which is the power) is

P=F_d v

and substituting

F_d = 1.288\cdot 10^6 N\\v = 250 m/s

we find

P=(1.288\cdot 10^6)(250)=3.22\cdot 10^8 W

Converting into horsepower,

P=\frac{3.22\cdot 10^8}{746}=4.32\cdot 10^5 hp

4 0
2 years ago
A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the m
Marrrta [24]

Answer:

-1.47 m/s^2

Explanation:

We can use the following SUVAT equation to solve the problem:

v^2 - u^2 = 2ad

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

a=\frac{v^2-u^2}{2d}=\frac{0-(24)^2}{2(196)}=-1.47 m/s^2

4 0
2 years ago
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