Question

A car came to a stop from a speed of 35 m/s in a time of 8.1 seconds. What was the acceleration of the car?

Answer 1

Simply subtract the two velocities and divide by 8.1,

$\frac{0 - 35}{8.1} = - 4.32$

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

Answer 2

Answer:

The acceleration of the car is -4.32 m/s^2.

(C) is correct.

Explanation:

Given that,

Speed of car u= 35 m/s

Time t = 8.1 s

We need to calculate the acceleration

using equation of motion

$v = u+at$

Where, v = final velocity

u = initial velocity

t = time

a = acceleration

$0=35+a\times8.1$

$a = -\dfrac{35}{8.1}$

$a = -4.32\ m/s^2$

Hence, The acceleration of the car is -4.32 m/s^2.