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alex41 [277]
2 years ago
15

A 72 kg skydiver is descending on a parachute. His speed is still increasing at 1.2 m/s2. What are the magnitude and direction o

f the force of the parachute harness on the diver? What are the magnitude and direction of the net force on the diver?
Physics
1 answer:
frozen [14]2 years ago
8 0

Answer:

86.4 N downward

Explanation:

Force: This can be defined as the product of mass and acceleration of a body.

The S.I unit of Force is Newton(N).

The Expression of force is given as,

F = ma ................ Equation 1

Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.

Given: m = 72 kg, a = 1.2 m/s²

Substitute into equation 1

F = 72(1.2)

F = 86.4 N down ward.

Hence the force on the parachute harness = 86.4 N downward

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Answer:

The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

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mass of the truck, m_t = 2490 kg

mass of the car, m_c = 890 kg

let the acceleration of the car at the moment they collided = a_c

Apply Newton's third law of motion;

Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2

Therefore, the magnitude of the acceleration of the car is 35.53 m/s²

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Let's plug the given values in the formula.

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