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Lady_Fox [76]
2 years ago
6

José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be remo

ved without the riders falling. When the ride accelerates to a speed of 17.0 m/s, his angular momentum is 3570 kg m2/s. What is his mass?
Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits
Physics
1 answer:
zaharov [31]2 years ago
8 0

r = radius of the circle of the ride = 3.00 meters

v = linear speed of the person during the ride = 17.0 m/s

m = mass of the person in angular motion in the ride

L = angular momentum of the person in the ride = 3570 kg m²/s

Angular momentum is given as

L = m v r

inserting the values

3570 kg m²/s = m (17 m/s) (3.00 m)

m = 3570 kg m²/s/(51 m²/s)

m = 7 kg

hence the mass comes out to be 7 kg


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The free-body diagram of a crate is shown. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N
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As per given conditions there are two directions along which forces are acting

1. Net force along left direction is given as

F_{left} = 352N + 176 N = 528 N

2. Net force towards right direction is given as

F_{right} = 528N + 440 N = 968 N

now since the two forces here in opposite direction so here we will have net force given as

F_{net} = F_{right} - F_{left}

F_{net} = 968 - 528

F_{net} = 440 N

so here net forces must be 440 N towards right

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2 years ago
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frosja888 [35]
Lucite has a refractive index of n=1.50. This means that the speed of the light in lucite is decreased according to:
v=\frac{c}{n}
where c=3 \cdot 10^8 m/s is the speed of light in air. Putting the number in the formula, we find that the speed of light in lucite is
v=\frac{3 \cdot 10^8 m/s}{1.50}=2\cdot 10^8 m/s
The frequency of the light is f=5.09 \cdot 10^{14}Hz, so now we can calculate the wavelength in lucite by using the formula:
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The temperature and pressure at the surface of Mars during a Martian spring day were determined to be -50 °C and 900 Pa, respect
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Answer:

T = 273 + (-50) = 273 – 50 = 223 K

R = 188.82 J / kg K for CO2

Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / m^{3}

T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa

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2 years ago
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larisa [96]

Answer:

longitudinal wave

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2 years ago
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Kobotan [32]

Answer:

Explanation:

Given that,

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