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morpeh [17]
2 years ago
7

Based on the emf value measured at frame 700, what is the average magnitude of the magnetic field inside the magnet assembly? No

te that the loop has 10 turns; in other words, the total emf is the sum of the emf’s generated in each turn. In your calculations, use 26 mV for the magnitude of the total induced emf and 0.060 m/s for the speed of the loop.
Physics
1 answer:
Nadusha1986 [10]2 years ago
4 0

Answer:

The average magnitude of magnetic field B= 0.0433/ d Tesla

(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)

Explanation:

Induced emf

where B= magnetic field  

d= breadth of rectangular piece

V= velocity with which the rectangular piece = o.o6m/s

n= no of turns  = 10

EMF = 26mV

since d (breadth of the frame) is not given, I will use it as a variable

EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)

From eq 1, we get

B= (EMF)/(n d V)

B= (26 X 0.001) / (10 d 0.06)

B= 0.0433/ d Tesla

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Answer:

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y axis

initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration

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the sign indicates that the acceleration goes in the negative direction of the y axis

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A 13,000-N vehicle is to be lifted by a 25-cm diameter hydraulic piston. What force needs to be applied to a 5.0 cm diameter pis
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Answer:

Explanation:

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Imagine two people standing at placemark A and placemark E, looking at each other across the fault. Which of the following state
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To both observers, the land opposite them is moving to the right.

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I have this class too. and there is also a quizlet with all the answers to the rest of the other questions. Trust me its right .

https://quizlet.com/261219090/oce-1001-chapter-2-flash-cards/

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A Porsche challenges a Honda to a 200-m race.Because the Porsche's acceleration of 3.5 m/s2 is larger than the Honda's 3.0 m/s2,
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