Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the h
igher track? _________
a. cars travel faster on the lower track
b. cars travel faster on the higher track
c. There is no difference in speed
How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is__________
a. Shorter
b. Longer
c. Equal
Calculate speeds for each track. How much faster was the car on the higher track than the lower track?__________
a. .56 m/s
b. 1.54 m/s
c. 3.50 m/s
a. cars travel faster on the lower track
b. cars travel faster on the higher track
c. There is no difference in speed
How can the reasoning for the above answer be best explained? On the higher track, the elapsed time is__________
a. Shorter
b. Longer
c. Equal
Calculate speeds for each track. How much faster was the car on the higher track than the lower track?__________
a. .56 m/s
b. 1.54 m/s
c. 3.50 m/s
2 answers:
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Answer:
Dₓ = -155 sin 23° i + 0 j
Explanation:
The diagram showing the vector has been attached to this response.
As shown in the diagram,
The vector D has an x-component (also called horizontal component) of -D sinθ i. i.e
Dₓ = -D sin θ i [The negative sign shows that D lies in the negative x direction]
Where;
D = magnitude of D = 155m
θ = direction of D = 23°
Therefore;
Dₓ = -155 sin 23° i
Since Dₓ represents the x component, its unit vector, j component has a value of 0.
Therefore, Dₓ can be written in terms of D, θ and the unit vectors i and j as follows;
Dₓ = -155 sin 23° i + 0 j
Answer:900 feet
Explanation:
Given
Velocity
it take 100 feet to stop
Using Equation of motion
where
v,u=Final and initial velocity
a=acceleration
s=distance moved
When velocity is 60 mph
s=900.08 feet