Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
Answer:
<em>The Answer is both B and C, </em><em>since it has same options from the question given. Gear, slow her vehicle in a lower</em>
Explanation:
<em>The use of a lower gear in a vehicle helps a person to control their speed limits, when approaching a hill. it also saves the brakes too, using the brakes down a hill can overheat the gear and causes brake failures</em>
<em>By changing in into a lower gear and also letting the engine to do the brake work in a vehicle, the engine will absorb a force and slow the vehicle down, but in most cases brakes can be applied but with lesser pressure.</em>
<em>In this case Stella need to slow down by applying her lower gear down a hill to avoid accidents on the road, by controlling her speed limits and for safety precaution</em>
Answer:
a) 1.2*10^-7 m
b) 1.0*10^-7 m
c) 9.7*10^-8 m
d) ultraviolet region
Explanation:
To find the different wavelengths you use the following formula:
RH: Rydberg constant = 1.097 x 10^7 m^−1.
(a) n=2
(b)
(c)
(d) The three lines belong to the ultraviolet region.
Answer:
A) 0.33 m/s
Explanation:
The standard form of a transverse wave is given by
y
=
a cos
(
ω
t
−
kx
) , k
= 2
π / λ
Amplitude, a
= 0.002 m
Wavenumber (k)=47.12 and wavelength (
λ
) = 0.133
m
Time period(T)=0.0385 s and angular frequency (
ω
) = 52
π rad/s
Maximum speed of the string is given by aw
Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s
