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2 years ago

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An apple is whirled round in a horizontal circle on the end of a string which is tied to the stalk. It is whirled faster and fas

ter and at a certain speed the apples is torn from the stalk.Why?

1 answer:

Brrunno [24]2 years ago

6 0

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

T=mv²/r

where T = tension force in the string , m = mass of the apple

v = speed of apple , r = radius of circle.

clearly , tension force depends on the square of the speed. hence greater the speed, greater will be the tension force.

at some point , the speed becomes large enough that it makes the tension force in the string becomes greater than the tensile strength of the string. at that point , the string breaks

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You are stranded in a blizzard. You need water to drink to drink,and you're trying to stay warm.should the melt the snow and dri

Crazy boy [7]

It would be a really bad idea to eat the snow because you obviously are trying to stay warm right? Well, the best thing to do is melt the snow. However, the process of melting the snow would have a few complications as well. But yes, the latter idea (drinking the snow) is a better idea (not the best).

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2 years ago

A 900-kg car traveling east at 15.0 m/s collides with a 750-kg car traveling north at 20.0 m/s. The cars stick together. Assume

dalvyx [7]

Explanation:

It is given that,

Mass of the car 1, $m_1=900\ kg$

Initial speed of car 1, $u_1=15i\ m/s$ (east)

Mass of the car 2, $m_2=750\ kg$

Initial speed of car 2, $u_1=20j\ m/s$ (north)

(b) As the cars stick together. It is a case of inelastic collision. Let V is the common speed after the collision. Using the conservation of momentum as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

$900\times 15i +750\times 20j=(900+750)V$

$13500i+15000j=1650V$

$V=(8.18i+9.09j)\ m/s$

The magnitude of speed,

$|V|=\sqrt{8.18^2+9.09^2}$

V = 12.22 m/s

(b) Let $\theta$ is the direction the wreckage move just after the collision. It is given by :

$tan\theta=\dfrac{v_y}{v_x}$

$tan\theta=\dfrac{9.09}{8.18}$

$\theta=48.01^{\circ}$

Hence, this is the required solution.

4 0

2 years ago

The diagram below depicts all the forces acting on an object. Use both vector resolution and vector

maksim [4K]

Answer:

A

Explanation:

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3 0

2 years ago

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.

grin007 [14]

<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium

So

RI = 1/0.6 = 5/3 or 1.66

3 0

2 years ago

Read 2 more answers

The atmosphere pressure can support mercury in a tube, which the upper end is closed, up to 0.76 meter. If the mercury is replac

Leni [432]

Answer:

Maximum height the atmosphere pressure can support the

water=10.336 m

Explanation:

We know that ,

$Pressure = h\cdot\rho\cdot g$

Case 1 - Mercury in the tube

$Density\ of\ mercury =\rho_1\\and\ height\ attained\ for\ mercury\ column = h_1$

Case 2 - Water in the tube

$Density\ of\ water =\rho_2\\and\ height\ attained\ for\ water\ column = h_2$

Since atmospheric pressure is same

. $P=h_1\cdot\rho_1\cdot g = h_2\cdot\rho_2\cdot g$

or, $h_2=\frac{h_1\rho_1}{\rho_2}$

$Given\ h_1= 0.76\ m,\rho_1=13.6\cdot\rho_2$

∴ $h_2=0.76\cdot13.6=10.336\ m$

Hence height of the water column =10.336 m

6 0

2 years ago