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Romashka-Z-Leto [24]
2 years ago
10

Find your mass if a scale on earth reads 650 N when you stand on it.

Physics
1 answer:
netineya [11]2 years ago
7 0

Weight = (mass) x (gravity)

Acceleration of gravity on Earth = 9.8 m/s²

                                           Weight on Earth = (mass) x (9.8 m/s²)

Divide each side by  (9.8 m/s²):          Mass = (weight) / (9.8 m/s²)

                                                            Mass = (650 N) / (9.8 m/s²)

                                                           Mass = 66.33 kg  (rounded)
 
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rusak2 [61]
We are missing an important piece of information needed to answer this question: the number of kcal Charles losses per day. However, we can come up with a general equation in which kcal/day is the only independent variable.

We know that it takes 3500 kcal to lose one pound. To lose 5 pounds, Charles needs to lose 5 x 3500 kcal = 17,500 kcal. 

To find how many days it takes Charles to lose 17,500 kcal (5 pounds), we must divide that amount by the number of kcal Charles loses per day. 
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Number of days= 17500 / (kcal per day)

If given calories, remember that 1000 calories = 1 kcal, and .001 kcal = 1 cal

4 0
2 years ago
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receiv
Lina20 [59]

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

7 0
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Water is formed when two hydrogen atoms bond to an oxygen atom. The hydrogen and the oxygen in this example are different A) com
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Read 2 more answers
A radiator rests snugly on the floor of a room when the temperature is 10 oC. The radiator is connected to the furnace in the ba
s344n2d4d5 [400]
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Explanation subtract
8 0
2 years ago
What is the electric potential vtot at the center of the square? make the usual assumption that the potential tends to zero far
Romashka-Z-Leto [24]
Missing figure of the problem: http://tsephysics.weebly.com/uploads/5/1/9/3/51934203/477140_orig.jpg

Solution:
Assuming the potential is zero at infinite distance from the charge, then the potential at a certain distance r from a single point charge is 
V(r)=k_e  \frac{q}{r}
where k_e=8.99\cdot 10^9 Nm^2C^{-2} is the Coulomb's constant.

In our problem, we just have to superimpose the potential generated by every charge. The diagonal of the square is \sqrt{2} d, therefore the distance between each charge and the center of the square is \frac{ \sqrt{2} }{2} d.
So, the total potential is:
V=V_1+V_2+V_3+V_4=
=k_e \frac{q}{ \frac{ \sqrt{2}d }{2} }+ k_e \frac{2q}{ \frac{ \sqrt{2}d }{2} }+k_e \frac{5q}{ \frac{ \sqrt{2}d }{2} }-k_e \frac{3q}{ \frac{ \sqrt{2}d }{2} }=
=5 \sqrt{2} k_e  \frac{q}{d}
7 0
2 years ago
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