Option (a) is correct.
Change in volume during the band concert might have been caused by the constructive and destructive interference of sound waves.
Interference is the process of redistribution of energy when two or more waves superimpose on each other.When two sound waves which are in phase superimpose on each other, constructive interference takes place. During constructive interference , the amplitude of resulting waves increases.Thus the loudness of sound increases.
When two sound waves which are out of phase superimpose on each other, destructive interference takes place. During destructive interference , the amplitude of resulting waves decreases.Thus the loudness of sound decreases.
When block is pushed upwards along the inclined plane
the net force applied on the block will be given as
here we know that
m = 75 kg
now plug in all values into this
now for finding the power is given as
Answer:
a) V_a = -5.7536 10⁺⁷ V
, b) Vb = -1.92 10⁻⁷ V c) the sign of the potential change
Explanation:
The electrical potential for a point charge
V = k q / r
Where k is the Coulomb constant that you are worth 8.99 10⁹ N m² / C²
a) potential At point x = 0.250 cm = 0.250 10-2m
V_a = -8.99 10⁹ 1.6 10⁻¹⁹ /0.250 10⁻²
V_a = -5.7536 10⁺⁷ V
b) point x = 0.750 cm = 0.750 10-2
Vb = 8.99 10⁹ (-1.6 10⁻¹⁹) /0.750 10⁻²
Vb = -1.92 10⁻⁷ V
potemcial difference
ΔV = Vb- Va
V_ba = (-5.7536 + 1.92) 10⁻⁷
V_ba = -3.83 10⁻⁷ V
c) To know what would happen to a particle, let's use the relationship between the potential and the electric field
ΔV = E d
The force on the particle is
F = q₀ E
F = q₀ ΔV / d
We see that the force on the particle depends on the sign of the burden of proof. Now the burden of proof is negative to pass between the two points you have to reverse the sign of the potential, bone that the value should be reversed
V_ba = 0.83 10⁻⁷ V
The other scale will either have a higher or lower number because 400 could be the bigger number or the smaller number but we don't know that so you cant exactly answer it.<span />
The magnitude of the E-field decreases as the square of the distance from the charge, just like gravity.
Location ' x ' is √(2² + 3²) = √13 m from the charge.
Location ' y ' is √ [ (-3)² + (-2)² ] = √13 m from the charge.
The magnitude of the E-field is the same at both locations.
The direction is also the same at both locations ... it points toward the origin.
