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2 years ago

8

The diagram shows a heater above a thermometer. The thermometer bulb is in the position shown. Which row shows how the heat ener

gy from the heater reaches the thermometer bulb?

1 answer:

balu736 [363]2 years ago

5 0

Answer:

The diagram shows a heater above a thermometer. The thermometer bulb is in the position shown. How the heat

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To support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. T

podryga [215]

Answer:

The wire meet the ground at an angle of 56.4 degrees

Explanation:

It is given that,

To support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.

The hypotenuse is, H = 12 foot

The perpendicular distance is, P = 10 feet

The angle between the tree and the ground is 90 degrees

Using Pythagoras theorem as :

$sin\theta=\dfrac{P}{H}$

$sin\theta=\dfrac{10}{12}$

$\theta=56.4^{\circ}$

So, the wire meet the ground at an angle of 56.4 degrees. Hence, the correct option is (d).

6 0

1 year ago

Dee is on a swing in the playground. the chains are 2.5 m long, and the tension in each chain is 450 n when dee is 55 cm above t

Leno4ka [110]

Refer to the diagram shown below.

From the geometry, obtain
x = 2.5 - 0.55 = 1.95 m
cos θ = 1.95/2.5 = 0.78
θ = cos⁻¹ 0.78 = 38.74°

From the free body diagram, the tension in the chain is 450 N.
F is the centripetal force,
W is Dee's weight.

The components of the tension are
Horizontal component = 450 sin(38.74°) = 281.6 N, acting left.
Vertical component = 450 cos(38.74°) = 351.0 N, acting upward.

Answers:
Horizontal: 281.6, acting left.
Vertical: 351.0 N, acting upward.

8 0

2 years ago

Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det

chubhunter [2.5K]

Complete Question

The complete quetion is shown on the first uploaded image

Answer:

Explanation:

From the question we are told that

The mass of the fly is $m_f = 11 mg = 11*10^{-3} g = 1.1*10^{-5} \ kg$

The extension of the web is $e= 4.00 \ mm = 0.004 \ m$

The spring constant is mathematically evaluated as

$k = \frac{mg}{e}$

substituting values

$k = \frac{1.1 *10^{-5} *9.8}{0.004}$

$k = 0.027 \ N/m$

The frequency of vibration is

$f = \frac{1}{2 \pi} \sqrt{\frac{k}{m} }$

substituting values

$f = \frac{1}{2 * 3.142 } \sqrt{\frac{0.027}{1.1*10^{-5}} }$

$f = 7.9 Hz$

8 0

1 year ago

Approximating Venus's atmosphere as a layer of gas 50 km thick, with uniform density 21 kg/m3, calculate the total mass of the a

Eduardwww [97]

Answer:

m = 4.9 10⁸ kg

Explanation:

The expression for the density is

ρ = m / V

m = ρ V

the volume of the atmosphere is the volume of the sphere of the outer layer of the atmosphere minus the volume of the plant

V = V_atmosphere - V_planet

V = 4/3 π R_atmosphere³ - 4/3 π R_venus³

V = 4/3 π (R_atmosphere³ - R_venus³

)

the radius of the planet is R_venus = 6.06 10⁶ m.

The radius of the outermost layer of the atmosphere

R_atmosphere = 50 10³ + R_ venus = 50 10³ + 6.06 10⁶

R_atmosphere = 6.11 10⁶ m

let's find the volume

V = 4/3 pi [(6,11 10⁶)³ - (6,06 10⁶)³]

V = 23,265 10⁶ m³

let's calculate the mass

m = 21 23,265 10⁶

m = 4.89 10⁸ kg

with two significant figurars is

m = 4.9 10⁸ kg

3 0

2 years ago

A helicopter flies 250 km on a straight path in a direction 60° south of east. The east component of the helicopter's

Savatey [412]

Answer:

The east component of the helicopter's displacement is 125 km.

Explanation:

Given:

The magnitude of displacement is, $S=250\ km$

The direction of displacement is 60° south of east.

The direction is shown in the figure below. From the figure, the horizontal component of the displacement vector is the east component.

Thus, the east component of displacement is given as:

$S_{x}=S\cos 60\°\\S_x=250\times \frac{1}{2}=125\ km$

Hence, the east component of the helicopter's displacement is 125 km.

7 0

2 years ago

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