Answer:
Fc = 7.14N
Explanation:
First of all, let's convert everything to the same unit system:
m = 0.0031kg R = 13.1cm * 1m / 100cm = 0.131m
ω = 50000 rev/min * 1rev /( 2π rad ) * 1min / 60s = 132.63 rad/s
Now we can calculate centripetal force as:
Replacing the values we get the answer:
Fc = 7.14N
Answer:
<em>The final charge on the 6.0 mF capacitor would be 12 mC</em>
Explanation:
The initial charge on 4 mF capacitor = 4 mf x 50 V = 200 mC
The initial Charge on 6 mF capacitor = 6 mf x 30 V =180 mC
Since the negative ends are joined together the total charge on both capacity would be;
q =
q = 200 - 180
q = 20 mC
In order to find the final charge on the 6.0 mF capacitor we have to find the combined voltage
q = (4 x V) + (6 x V)
20 = 10 V
V = 2 V
For the final charge on 6.0 mF;
q = CV
q = 6.0 mF x 2 V
q = 12 mC
Therefore the final charge on the 6.0 mF capacitor would be 12 mC
Answer:
a = 18.28 ft/s²
Explanation:
given,
time of force application, t= 10 s
Work = 10 Btu
mass of the object = 15 lb
acceleration, a = ? ft/s²
1 btu = 778.15 ft.lbf
10 btu = 7781.5 ft.lbf
m = 0.466 slug
now,
work done is equal to change in kinetic energy
now, acceleration of object
a = 18.28 ft/s²
constant acceleration of the object is equal to 18.28 ft/s²