Answer:
0
Explanation:
Assuming your graph and question match the attachment, the average speed is 0. The bug ends up where it started, so its displacement is zero.
average speed = displacement/time = 0/(8 s)
average speed = 0
Answer:
5.22 x 10^5 V
Explanation:
guessed on castle learning and got it right
Answer:
V_infinty=98.772 m/s
Explanation:
complete question is:
The following problem assume an inviscid, incompressible flow. Also, standard sea level density and pressure are 1.23kg/m3(0.002377slug/ft3) and 1.01imes105N/m2(2116lb/ft2), respectively. A Pitot tube on an airplane flying at standard sea level reads 1.07imes105N/m2. What is the velocity of the airplane?
<u>solution:</u>
<u>given:</u>
<em>p_o=1.07*10^5 N/m^2</em>
<em>ρ_infinity=1.23 kg/m^2</em>
<em>p_infinity=1.01*10^5 N/m^2</em>
p_o=p_infinity+(1/2)*(ρ_infinity)*V_infinty^2
V_infinty^2=9756.097
V_infinty=98.772 m/s
Answer:
h=20.66m
Explanation:
First we need the speed when the cord starts stretching:
This will be our initial speed for a balance of energy.
By conservation of energy:
Where
is your height at its maximum elongation
is the height of the bridge
is the length of the unstretched bungee cord
Solving for h:
and 
Since 99m is higher than the initial height of 79m, we discard that value.
So, the final height above water is 20.66m
Fnet=(115+106)-186= 34 N
mass=Force/g= 186N/9.8m/s^2 = 18.98 kg
a=fnet/mass => 34N/18.98kg = 1.79 m/s^2
so A= 1.8m/s^2
