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Tcecarenko [31]
1 year ago
12

One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on

a lab bench for one week. At the end of the week, the liquid in both beakers has decreased, however, the level has decreased more in one of the beakers than in the other. Explain why one of them has decreased more by filling in the following sentence:
Physics
2 answers:
Harman [31]1 year ago
7 0

Answer: The beaker containing pure water has decreased more.

Explanation:

In both cases, the decrease of water level is due to evaporation. We know that evaporation is a surface phenomenon. In the case of salt water, the salt molecules somewhat hinders the evaporation process of the water molecules and hence the salt water evaporates at a slower rate than pure water.

Hence, pure water level falls more.

marishachu [46]1 year ago
4 0

Answer:

The answer is:

The presence of the dissolved salt in the sea water means that there is a lower number of water molecules at the surface. This therefore means that the sea water will have lower rate of vaporization than the pure water which is why the water level in the sea water beaker is higher by the end of the weak.

Explanation:

Pure water is characterized by being only made up of water molecules. Only those molecules will exist on its surface. On the other hand, seawater is made up of different types of ions, other chemical compounds, etc. In the glass that contains sea water on its surface there will be different dissolved molecules, in addition to the water molecules. In this way, the number of water molecules will be less compared to pure water. Regarding the evaporation rate, in pure water it is higher than that of sea water. This is why the glass that only contains pure water will evaporate much faster than the glass that contains sea water.

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Stacy measures two quantities: the mass of each washer and the force that the washers exert on the force meter. In general, how
geniusboy [140]

Answer:

When she adds more washers to the meter, the magnitude of force that is shown on the force meter increases.

Explanation:

The force that the washers exert on the force meter is actually the weight of the washers. Weight is actually a force with gravitation acceleration.

                       F = W = mg

Where g is gravitational acceleration and its value is 9.81 m/s² and m is the mass of any object. As she adds more washers to the meter so the total mass of the washers increases. As the mass of the washers increases, magnitude of the force (Weight) shown on the force meter increases.

6 0
2 years ago
The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f
tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0
1 year ago
A pyrotechnical releases a 3 kg firecracker from rest. at t=0.4 s, the firecracker is moving downward with a speed 4 m/s. At the
olga2289 [7]

Answer:

a) F = 30 N, b)   I = 12 N s , c)  I = -12 N s , d) ΔI = 0 N s

Explanation:

This exercise is a case at the moment, let's define the system formed by the firecracker and its two parts, in this case the forces during the explosion are internal and the moment is conserved

Initial, before the explosion

     p₀ = m v

The speed can be found by kinematics

     v = v₀ - g t

     v = 0 - 10 0.4

     v = -4.0 m / s

Final after division

     pf = m₁ v₁f + m₂ v₂f

    p₀ = pf

    M v = m₁ v₁f + m₂ v₂f

Where M is the initial mass (M = 3 kg), m₁ is the mass mtop (m₁ = 1 kg) and m₂ in the mass m botton (m₂ = 2kg) and the piece that moves up (v₁f = 6m/s )

a) before the explosion the only force acting on the body is gravity

     F = mg

     F = 3 10 = 30 N

b) The expression for momentum is

     I = Ft

Before the explosion the only force that acts is the weight

    I = mg t

    I = 3 10 0.4

    I = 12 N s

c) To calculate this part we use the conservation of the moment and calculate the speed of the body that descends body 2

    M v = m₁ v₁f + m₂ v₂f

    v₂f = (M v - m₁ v₁f) / m₂

    v₂f = (3 (-4) - 1 6) / 2

   v₂f = - 9 m / 2

The negative sign indicates that body 2 (botton) is descending

Now we can use the momentum and momentum relationship for the body during the explosion

    I = F t = Dp

   F t = pf –po)

   F t= [m₁ v₁f + m₂ v₂f]

   

   I = [1 6 + 2 (-9) -0]

   I = -12 N s

This is the impulse during the explosion the negative sign indicates that it is headed down

d) impulse change

I₀ = Mv

I₀ = 3 *4

I₀ =-12 N s

 ΔI =If – I₀  

ΔI = - 12 – (-12)

ΔI = -0 N s

3 0
2 years ago
The primary additive colors are red, green, and blue, which means that any color can be constructed from a linear superposition
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3 0
1 year ago
A driver's foot presses with a steady force of 20N on a pedal in a car as shown.
azamat

Answer:

160N

Explanation:

Moments must be conserved - so.

20 * 0.4 = F * 0.05

F=\frac{20*0.4}{0.05} = 160

6 0
2 years ago
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