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IgorLugansk [536]
2 years ago
13

750 million years ago, there was enough Uranium-235 present in Oklo, Gabon to have a natural fission reactor occur and generate

a chain reaction. If there is currently 50kg of U-235 present in Oklo, how much must have been present 750 million years ago when the reaction took place?
Physics
2 answers:
Komok [63]2 years ago
3 0
<span>With a half-life of 700 million years, U-235 would have had twice as much mass at a time 700 MYA. This would have put the mass at 100kg at that time. Going back another 50 million years would be (50/700) or 1/14 of the half-life, or (1/2 * 1/14), or 1/28 of the total mass. 1/28 of 100kg is 3.57kg, so the amount present at the 750MYA mark would be approximately 103.57kg of U-235.</span>
tiny-mole [99]2 years ago
3 0

Answer

B

Explanation: i had that same question

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What is the instantaneous velocity of a freely falling object 9.0 s after it is released from a position of rest? Express your a
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Answer:

So instantaneous velocity after 9 sec will be 88.2 m/sec              

Explanation:

We have given time t = 9 sec

As the object is released from rest so its initial velocity u = 0 m/sec

We have to find its final velocity v

Acceleration due to gravity g=9.8m/sec^2

From first equation of motion we know that v=u+gt

v=0+9.8\times 9=88.2m/sec

So instantaneous velocity after 9 sec will be 88.2 m/sec  

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An electric buzzer is activated, then sealed inside a glass chamber. When all of the air is pumped out of the chamber, how is th
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An green hoop with mass mh = 2.8 kg and radius rh = 0.13 m hangs from a string that goes over a blue solid disk pulley with mass
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The only force on the system is the mass of the hoop F net = 2.8kg*9.81m/s^2 = 27.468 N The mass equal of the rolling sphere is found by: the sphere rotates around the contact point with the table. 
So by applying the theorem of parallel axes, the moment of inertia of the sphere is computed by:I = 2/5*mR^2 for rotation about the center of mass + mR^2 for the distance of the axis of rotation from the center of mass of the sphere. 
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2 years ago
Which letter correctly identifies the part of the hydrologic cycle that is most directly affected by impervious building materia
masha68 [24]

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The component of the hydrologic cycle affected by impervious building such as concrete and asphalt is infiltration.

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learn more:

Biogeochemical cycle brainly.com/question/3509510

#learnwithBrainly

3 0
2 years ago
A hot (70°C) lump of metal has a mass of 250 g and a specific heat of 0.25 cal/g⋅°C. John drops the metal into a 500-g calorimet
Gnom [1K]

Answer:

d. 37 °C

Explanation:

m_{m} = mass of lump of metal = 250 g

c_{m} = specific heat of lump of metal  = 0.25 cal/g°C

T_{mi} = Initial temperature of lump of metal = 70 °C

m_{w} = mass of water = 75 g

c_{w} = specific heat of water = 1 cal/g°C

T_{wi} = Initial temperature of water = 20 °C

m_{c} = mass of calorimeter  = 500 g

c_{c} = specific heat of calorimeter = 0.10 cal/g°C

T_{ci} = Initial temperature of calorimeter = 20 °C

T_{f} = Final equilibrium temperature

Using conservation of heat

Heat lost by lump of metal = heat gained by water + heat gained by calorimeter

m_{m} c_{m} (T_{mi} - T_{f}) = m_{w} c_{w} (T_{f} - T_{wi}) +  m_{c} c_{c} (T_{f} - T_{ci}) \\(250) (0.25) (70 - T_{f} ) = (75) (1) (T_{f} - 20) + (500) (0.10) (T_{f} - 20)\\T_{f} = 37 C

6 0
2 years ago
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