No because an atom consists of <u>two</u> main parts <em>and</em> <u>three</u> subatomic particles - protons, neutrons, electrons. Each one is smaller than an atom, therefore they are subatomic particles. An atom only requires protons and electrons to be an atom - e.g. Hydrogen has 1 proton and 1 electron. Neutrons do not affect the overall charge of the atom, and only increase the atomic mass.
The collision is a form of inelastic collision because the
it forms a single mass after is collides. So it can be solve by momentum
balance
( 0.08 kg * 50 m/s ) + ( 0.06 kg * 50 m/s) = ( 0.08 + 0.06
kg ) v
V = 50 m/s
So the kinetic energy lost is
KE = 0.5 (50 m/s)^2) *( 0.14 – 0.08kg )
KE = 75 J
Explanation:
(a) Displacement of an object is the shortest path covered by it.
In this problem, a student is biking to school. She travels 0.7 km north, then realizes something has fallen out of her bag. She travels 0.3 km south to retrieve her item. She then travels 0.4 mi north to arrive at school.
0.4 miles = 0.64 km
displacement = 0.7-0.3+0.64 = 1.04 km
(b) Average velocity = total displacement/total time
t = 15 min = 0.25 hour

Hence, this is the required solution.
Answer:
Part A - 3N/m
Part B - see attachment
Part C - 4.9 × 10-³J
Part D - E = 1/2kd² + 1/2mv² + mgh
Explanation:
This problem requires the knowledge of simple harmonic motion for cimplete solution. To find the spring constant in part A the expression relating the force applied to a spring and the resulting stretching of the spring (hooke's law) is required which is F = kx.
The free body diagram can be found in the attachment. Fp(force of pull), Ft(Force of tension) and W(weight).
The energy stored in the pring as a result of the stretching of d = 5.7cm is 1/2kd².
Part D
Three forces act on the spring-monkey system and they do work in different forms: kinetic energy 1/2mv² , elastic potential
energy due to the restoring force in the spring or the tension force 1/2kd², and the gravitational potential energy mgh of the position of the system. So the total energy of the system E = 1/2kd² + 1/2mv² + mgh.
Change in velocity of larger moose: (1/3)v - v = -(2/3)v
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2
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