A spring stretches by 15cm when a mass of 300g hangs down from it,if the spring is then stretched an additional 10cm and release
1 answer:
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Answer:
a) 1.2*10^-7 m
b) 1.0*10^-7 m
c) 9.7*10^-8 m
d) ultraviolet region
Explanation:
To find the different wavelengths you use the following formula:
RH: Rydberg constant = 1.097 x 10^7 m^−1.
(a) n=2
(b)
(c)
(d) The three lines belong to the ultraviolet region.
The question is missing the diagram. Also, the choices must have pictorial representation. So, I have attached the missing diagram and the pictorial representation of the vectors.
Answer:
The correct representation is attached below. Force and acceleration will be towards the center of rotation while the velocity will be along the tangent to the circular motion. <u>Option (D).</u>
Explanation:
From the figure, we can conclude the following points:
1. The cylinder is under a uniform circular motion as the circular table is moving at constant speed.
2. For a circular motion, velocity acts along the tangent to the circular path.
3. For a circular motion, centripetal force acts on the body that causes it move around a circular path.
4 The direction of the centripetal force is radially inward towards the center of rotation.
5. The centripetal force causes a centripetal acceleration acting on the body.
6. From Newton's second law, the net acceleration of a body is in the same direction as that of the net force acting on it. So, centripetal acceleration also acts in the radially inward direction.
Therefore, from the above conclusions, it is clear that velocity will act in the horizontal direction at the given instance of time and force and acceleration will act vertically down for the given instance.
This is shown in the picture below. The option (D).
Answer:
The magnitude of the torque on the loop due to the magnetic field is .
Explanation:
Given that,
Diameter = 10 cm
Current = 0.20 A
Magnetic field = 0.30 T
Unit vector
We need to calculate the torque on the loop
Using formula of torque
Where, N = number of turns
A = area
I = current
B = magnetic field
Put the value into the formula
Hence, The magnitude of the torque on the loop due to the magnetic field is .