The acceleration is defined as the rate of change of velocity.
So, if the acceleration is zero, this means that the rate of change of velocity is zero, which also means that the body is moving with constant velocity.
Since we are given that the net forces acting on the body is zero, this means that the body is at equilibrium
Based on this:
<span>All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as equilibrium.
Note that if this constant velocity is equal to zero, then the body would be at rest (not moving)</span>
Answer:
Nails are made of iron. Iron consists of 26 protons and 26 electrons. protons are positively charged and electrons are negatively charged, so this force of attraction keeps the electrons together.
If electrons repel from each other, the positively charge protons and nucleus allow them to move in a definite orbit and prevent them flying out of the nail.
Answer:
Explanation:
The relationship between the frequency, the wavelength and the speed of a wave is given by the wave's equation:
where
v is the speed of the wave
f is the frequency
is the wavelength
For the pulse in this problem,
Solving for f, we find the frequency:
Answer: Change in ball's momentum is 1.5 kg-m/s.
Explanation: It is given that,
Mass of the ball, m = 0.15 kg
Speed before the impact, u = 6.5 m/s
Speed after the impact, v = -3.5 m/s (as it will rebound)
We need to find the change in the magnitude of the ball's momentum. It is given by :
So, the change in the ball's momentum is 1.5 kg-m/s. Hence, this is the required solution.
Read more on Brainly.com - brainly.com/question/12946012#readmore
Answer:
Explanation:
The attached image shows the system expressed in the question.
We can define an expression for the system.
The equivalent equation for the system would be
so, the input signal could be expressed in dB terms
![P_{in} [dB] = 10 log_{10}(P_{in}) \\P_{in} [dB] = 10 log_{10}(0.4)\\P_{in} [dB] = -3.97 dB](https://tex.z-dn.net/?f=P_%7Bin%7D%20%5BdB%5D%20%3D%2010%20log_%7B10%7D%28P_%7Bin%7D%29%20%5C%5CP_%7Bin%7D%20%5BdB%5D%20%3D%2010%20log_%7B10%7D%280.4%29%5C%5CP_%7Bin%7D%20%5BdB%5D%20%3D%20-3.97%20dB)
(1)
so the output signal could be expressed as.
The gain should be expressed in dB terms and power in dBm terms so
using the (1) equation to find it in terms of Watts
