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motikmotik
2 years ago
10

Which of the following statements are true?A. The decrease in the amplitude of an oscillation caused by dissipative forces is ca

lled damping. B. The increase in amplitude of an oscillation by a driving force is called forced oscillation. C. In a mechanical system, the amplitude of an oscillation diminishes with time unless the lost mechanical energy is replaced. D. An oscillation that is maintained by a driving force is called forced oscillation.
Physics
1 answer:
Umnica [9.8K]2 years ago
7 0

Answer:

right A, B, C, D

Explanation:

They ask which statements are true

A) Right. The decrease in amplitude is due to the dissipation of energy by friction and is called damping

B) Right. In resonant processes the amplitude of the oscillation increases, being a forced oscillation

C) Right. In a system with energy loss, the amplitude must decrease, therefore energy must be supplied to compensate for the loss.

D) Right. It is a resonant process the driving force keeps the oscillation of the system

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The U.S. Department of Energy had plans for a 1500-kg automobile to be powered completely by the rotational kinetic energy of a
navik [9.2K]

Answer:

230

Explanation:

\omega = Rotational speed = 3600 rad/s

I = Moment of inertia = 6 kgm²

m = Mass of flywheel = 1500 kg

v = Velocity = 15 m/s

The kinetic energy of flywheel is given by

K=\dfrac{1}{2}I\omega^2\\\Rightarrow K=\dfrac{1}{2}6\times 3600^2\\\Rightarrow K=38880000\ J

Energy used in one acceleration

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}1500\times 15^2\\\Rightarrow K=168750\ J

Number of accelerations would be given by

n=\dfrac{38880000}{168750}\\\Rightarrow n=230.4

So the number of complete accelerations is 230

8 0
2 years ago
Apply the impulse-momentum relation and the work-energy theorem to calculate the maximum value of t if the cake is not to end up
loris [4]
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8 0
2 years ago
The magnetic field around the head has been measured to be approximately 3.00×10−8 gauss . Although the currents that cause this
konstantin123 [22]

Answer:

3.81972\times 10^{-7}\ A

Explanation:

B = Magnetic field = 3\times 10^{-8}\ G

d = Diameter of loop = 16 cm

r = Radius = \frac{d}{2}=\frac{16}{2}=8\ cm

i = Current

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

The magnetic field of a loop is given by

B=\frac{\mu_0i}{2r}\\\Rightarrow i=\frac{B2r}{\mu_0}\\\Rightarrow i=\frac{3\times 10^{-8}\times 10^{-4}\times 2\times 0.08}{4\pi\times 10^{-7}}\\\Rightarrow i=3.81972\times 10^{-7}\ A

The current needed to produce such a field at the center of the loop is 3.81972\times 10^{-7}\ A

5 0
2 years ago
A particle of mass m= 2.5 kg has velocity of v = 2 i m/s, when it is at the origin (0,0). Determine the z- component of the angu
melomori [17]

Answer:

please read the answer below

Explanation:

The angular momentum is given by

|\vec{L}|=|\vec{r}\ X \ \vec{p}|=m(rvsin\theta)

By taking into account the angles between the vectors r and v in each case we obtain:

a)

v=(2,0)

r=(0,1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

b)

r=(0,-1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

c)

r=(1,0)

angle = 0°

r and v are parallel

L = 0kgm/s

d)

r=(-1,0)

angle = 180°

r and v are parallel

L = 0kgm/s

e)

r=(1,1)

angle = 45°

L = (2.5kg)(2\frac{m}{s})(\sqrt{2})sin45\°=5kg\frac{m}{s}

f)

r=(-1,1)

angle = 45°

the same as e):

L = 5kgm/s

g)

r=(-1,-1)

angle = 135°

L=(2.5kg)(2\frac{m}{s})(\sqrt{2})sin135\°=5kg\frac{m}{s}

h)

r=(1,-1)

angle = 135°

the same as g):

L = 5kgm/s

hope this helps!!

4 0
2 years ago
A battleship simultaneously fires two shells toward two identical enemy ships. One shell hits ship A, which is close by, and the
luda_lava [24]

Answer:

both cannonballs hit the ships with the same horizontal speed

Explanation:

Hello!

A parabolic motion is characterized in that its vertical component in Y is constantly changing, this is due to the constant downward acceleration of gravity.

When the movement starts the speed at Y is maximum, then when it reaches its maximum height point its speed is zero, and finally it begins to increase downwards until it touches the floor.

On the other hand, the horizontal speed remains constant AS THERE IS NO ACCELERATION IN HORIZONTAL DIRECTION.

therefore both cannonballs hit the ships with the same horizontal speed

regards!

8 0
2 years ago
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