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2 years ago

8

A handbag weighing 162N is carried by two students each holding the handle of the bag next to him. If each handle is inclined at

60° to the vertical, find the force on each student's arm

1 answer:

Mashcka [7]2 years ago

3 0

Answer:

162N

Explanation: resolving into components and equating both vertical components equal to 162 as explained in attachment

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A 1.00-kilogram ball is dropped from the top of a building. just before striking the ground, the ball's speed is 12.0 meters per

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During the fall, the potential energy stored in the ball is converted into kinetic energy.
Thus,
PE = KE before hitting the ground
= 1/2 • mv^2
= 1/2 • 1 • 12^2
= 72J

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The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu

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2 years ago

The different in size of each of the rope's pullers, correspond to a difference in the magnitude of the applied force, such that

olga55 [171]

Answer:

F = - 50 N

Hence, the magnitude of resultant force is 50 N and its direction is leftwards.

Explanation:

The magnitude of the resultant force is always equal to the sum of all forces. While, the direction of resultant force will be equal to the direction of the force with greater magnitude:

$Resultant\ Force = F = F_{1} - F_{2}$

considering right direction to be positive:

F₁ = Force applied on right rope = 150 N

F₂ = Force applied on left rope = 200 N

Therefore, the resultant force can be found by using these values in equation:

$F = 150\ N - 200\ N$

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2 years ago

A person drops a stone down a well and hears the echo 8.9 s later. if it takes 0.9 s for the echo to travel up the well, approxi

Temka [501]

Total time in between the dropping of the stone and hearing of the echo = 8.9 s

Time taken by the sound to reach the person = 0.9 s

Time taken by the stone to reach the bottom of the well = 8.9 - 0.9 = 8 seconds

Initial speed (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s^2

Time taken (t) = 8 seconds

Let the depth of the well be h.

Using the second equation of motion:

$h = ut + \frac{1}{2}\times a \times t^2$

$h = 0 \times 8 + \frac{1}{2} \times 9.8 \times 8^2$

h = 313.6 m

Hence, the depth of the well is 313.6 m

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2 years ago

At t1, Car A and car B are each located at position xo moving forward at speed v. At t2, car A is located at position 2xo moving

wel

Answer:

the average velocity of car A between t1 and t2greater is greater than the average velocity of B berween t1 and t2

Explanation:

Velocity is displacement over time,

Displacement is the distance covered relative to the initial starting position

For A:

at time ti, A moved from Xo to 2Xo, displacement is 2Xo.

at time t2 a moves with speed 3V, hence, his new position will be 3Xo from 2Xo which will be at 5Xo. A's displacement is 5Xo from starting point.

For B:

at time ti, B moved from Xo to 2Xo, displacement is 2Xo.

at time t2 a moves with speed V in the opposite position so he'll be back to his starting point, hence, his new position will be at Xo. A's displacement is 0 from his starting point.

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2 years ago