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hichkok12 [17]
2 years ago
9

You are given two rectangular blocks of shiny metal, Block A and Block B, and are asked to determine which one will float in a b

ath of mercury (a metal that is liquid at room temperature). Block A is 10 cm long, 6 cm wide and 1 cm high and has a mass of 630 g. Block B is 5 cm long, 5 cm wide, 3 cm high, and has a mass of 604 g. If mercury has a density of 13.6 g/cm3, which of the two blocks will float when placed in mercury?
Physics
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

Explanation:

Volume of block A = 10 x 6 x 1 = 60 cm³

Mass of block A = 630 g

density of mass A = mass / density

= 630 / 60 = 10.5g / cm³

Volume of block B = 5 x 5 x 3 = 75 cm³

Mass of block A = 604 g

density of mass A = mass / density

= 604 / 75 = 8.05 g / cm³

Since density of both A and B are less than that of mercury , both will float in mercury.

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A bathroom scales works due to gravity. Under normal conditions, a reading can be obtained when your body is pushing some force on the scale. However in this case, since you and the scale are both moving downwards, so your body is no longer pushing on the scale. Therefore the answer is:

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2 years ago
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Oceanographers use submerged sonar systems, towed by a cable from a ship, to map the ocean floor. In addition to their downward
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Answer:

Tension in the cable is T = 16653.32 N

Explanation:

Give data:

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 Drag force FD is given as

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As cable made angle  of 30 degree with horizontal  thus horizontal component is take into action to calculate drag force

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2 years ago
Light with a wavelength of 495 nm is falling on a surface and electrons with a maximum kinetic energy of 0.5 eV are ejected. Wha
devlian [24]

Answer:

To increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

Explanation:

First, we have to calculate the work function of the element. The maximum kinetic energy as a function of the wavelength is given by:

K_{max}=\frac{hc}{\lambda}-W

Here h is the Planck's constant, c is the speed of light, \lambda is the wavelength of the light and W the work function of the element:

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Now, we calculate the wavelength for the new maximum kinetic energy:

W+K_{max}=\frac{hc}{\lambda}\\\lambda=\frac{hc}{W+K_{max}}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{2.01eV+1.5eV}\\\lambda=3.54*10^{-7}m=354*10^{-9}m=354nm

This wavelength corresponds to ultraviolet radiation. So, to increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

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I think that your answer would be D
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