Answer:
the expression of current in the loop enclosed to the left of the capacitor plate is

Explanation:
As we know by Ampere's law that line integral of magnetic field around a closed loop is proportional to the current enclosed in the path
So we will have

so we have

so above is the expression of current in the loop enclosed to the left of the capacitor plate
The solution to your problem is as follows:
2.2Kg*9.8m/s = 21.56N
<span>
21.56N*1.25m = 26.95J </span>
<span>We're only concerned with the work done against gravity, lifting the books to 1.25 meters. the distance walked has no effect on the problem, unless you take into account the wind resistance and the force needed to overcome it. Also, lowering the books onto the shelf doesnt count, because gravity does the work on the books.</span>
I’m slightly confused about the wording of the question but if both the same y-intercept that means both company’s have the same flat rate charge for artwork.
Refer to the diagram shown below.
The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²
After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2
The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁
The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.
Conservation of energy requires that the loss in KE be accounted for as thermal energy.
Answer: 1/2
Answer:
Speed of the duck and bullet just after hit will be 2.4752 m/sec
Explanation:
We have given mass of the duck 
Velocity of the duck 
Mass of the bullet 
Velocity of the bullet 
From conservation of momentum we know that
Initial momentum = final momentum
So 


