Answer:
(i) 208 cm from the pivot
(ii) Move further from the pivot
Explanation:
(i) Sum of the moments about the pivot of the seesaw is zero.
∑τ = Iα
(50 kg) (10 N/kg) (2.5 m) + (60 kg) (10 N/kg) x = 0
1250 Nm + 600 N x = 0
x = -2.08 m
Kenny should sit 208 cm on the other side of the pivot.
(ii) To increase the torque, Kenny should move away from the pivot.
Answer:
P=740 KPa
Δ=7.4 mm
Explanation:
Given that
Diameter of plunger,d=30 mm
Diameter of sleeve ,D=32 mm
Length .L=50 mm
E= 5 MPa
n=0.45
As we know that
Lateral strain



We know that




So the axial pressure


P=740 KPa
The movement in the sleeve


Δ=7.4 mm
Answer:
Explanation:
Volume of block A = 10 x 6 x 1 = 60 cm³
Mass of block A = 630 g
density of mass A = mass / density
= 630 / 60 = 10.5g / cm³
Volume of block B = 5 x 5 x 3 = 75 cm³
Mass of block A = 604 g
density of mass A = mass / density
= 604 / 75 = 8.05 g / cm³
Since density of both A and B are less than that of mercury , both will float in mercury.
Answer:
The friend on moon will be richer.
Explanation:
We must calculate the mass of gold won by each person, to tell who is richer. For that purpose we will use the following formula:
W = mg
m = W/g
where,
m = mass of gold
W = weight of gold
g = acceleration due to gravity on that planet
<u>FOR FRIEND ON MOON</u>:
W = 1 N
g = 1.625 m/s²
Therefore,
m = (1 N)/(1.625 m/s²)
m(moon) = 0.6 kg
<u>FOR ME ON EARTH</u>:
W = 1 N
g = 9.8 m/s²
Therefore,
m = (1 N)/(9.8 m/s²)
m(earth) = 0.1 kg
Since, the mass of gold on moon is greater than the mass of moon on earth.
<u>Therefore, the friend on moon will be richer.</u>
Answer:
option A
Explanation:
given,
depth of the sea level = 10 m
g = 10 m/s²
Pressure underwater = ?
we know,
P = ρ g h
where ρ is the density of water which is equal to 1000 kg/m³
h is the depth of sea level
P = ρ g h
P = 1000 x 10 x 10
P = 100000 Pa
P = 100 kPa
Hence, the correct answer is option A