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Leviafan [203]
1 year ago
8

Which table correctly identifies the abbreviation for SI units of length mass volume and temperature

Physics
1 answer:
SIZIF [17.4K]1 year ago
8 0

Answer: b

Explanation:

Temperature: kelvin

Mass: kilogram

Length: Meter

Volume: Cubic meter

(Apex learning test)

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Consider a variety of colors of visible light (say 400 nm to 700 nm) falling onto a pair of slits.
babymother [125]

Answer:

Explanation:

The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by

For constructive interference

d\sin \theta =m\lambda

For Destructive interference

d\sin \theta =(m+\frac{1}{2})\lambda

where \lambda =wavelength

d=slit\ width

m=order of maxima and minima

for second order maxima i.e. m=2

For smallest separation taking \lambda =400 nm, \theta =90^{\circ}

d\sin 90=2\times 400\times 10^{-9}

d=0.8\times 10^{-6}

d=0.8\mu m

   

6 0
1 year ago
You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves along a frictionless track. however, af
djyliett [7]
I attached the missing picture.
We can figure this one out using the law of conservation of energy.
At point A the car would have potential energy and kinetic energy.
A: mgh_1+\frac{mv_1^2}{2}
Then, while the car is traveling down the track it loses some of its initial energy due to friction:
W_f=F_f\cdot L
So, we know that the car is approaching the point B with the following amount of energy:
mgh_1+\frac{mv_1^2}{2}- F_fL
The law of conservation of energy tells us that this energy must the same as the energy at point B. 
The energy at point B is the sum of car's kinetic and potential energy:
B: mgh_2+\frac{mv_2}{2}
As said before this energy must be the same as the energy of a car approaching the loop:
mgh_2+\frac{mv_2}{2}=mgh_1+\frac{mv_1^2}{2}- F_fL
Now we solve the equation for v_1:
v_1^2=2g(h_2-h_1)+v_2^2+\frac{2F_fL}{m}\\
v_1^2=39.23\\
v_1=\sqrt{39.23}=6.26\frac{m}{s}

4 0
1 year ago
Read 2 more answers
The diagram shows a heat engine. In which area of the diagram is unusable thermal energy detected?
Marat540 [252]
Nope, I disagree with the former answer. The answer is definitely Z. <u>W area</u> (boxed with red outline) is represented as the hot reservoir while <u>Z area</u> is the cold reservoir (boxed with blue outline). X area is the heat engine itself and Y area is the work produced from thermal energy from hot reservoir. Typically, all heat engines lose some heat to the environment (based from the second law of thermodynamics) that is symbolically illustrated by the lost energy in the cold reservoir. This lost thermal energy is basically the unusable thermal energy. The higher thermal energy lost, the less efficient your heat engine is. 
7 0
2 years ago
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Before a collision, the x-momentum of an object is 8.0 × 103 kilogram meters/second, and its y-momentum is 1.2 × 104 kilogram me
Georgia [21]
Physics
What is the momentum of a 1.5 × 103 kilogram van that is moving at a velocity of 32 meters/second? A. 46.9 kilogram meters/second B. 4.7 × 103 kilogram meters/second C. 4.85 × 102 kilogram meters/second D. 4.85 × 104 kilogram meters/second
6 0
2 years ago
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A helium ion of mass 4m and charge 2e is accelerated from rest through a potential difference V in vacuum. Its final speed will
Pavel [41]

Answer:

Final Velocity = √(eV/m)

Explanation:

The Workdone, W, in accelerating a charge, 2e, through a potential difference, V is given as a product of the charge and the potential difference

W = (2e) × V = 2eV

And this work is equal to change in kinetic energy

W = Δ(kinetic energy) = ΔK.E

But since the charge starts from rest, initial velocity = 0 and initial kinetic energy = 0

ΔK.E = ½ × (mass) × (final velocity)²

(Velocity)² = (2×ΔK.E)/(mass)

Velocity = √[(2×ΔK.E)/(mass)]

ΔK.E = W = 2eV

mass = 4m

Final Velocity = √[(2×W)/(4m)]

Final Velocity = √[(2×2eV)/4m]

Final Velocity = √(4eV/4m)

Final Velocity = √(eV/m)

Hope this Helps!!!

8 0
1 year ago
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