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2 years ago

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If 100 grams of vinegar and 5 grams of baking soda are poured in a container, a small amount of gas will be produced. What will

the final mass of the products be if the gas is trapped in the container?

1 answer:

Anit [1.1K]2 years ago

5 0

It will be a little bit less because of evaporation i learned that in third grade and your in high school that is sad

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Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what

hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² = k*1.6²

$k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}$

The value of the spring constant is 187,500N/m

7 0

2 years ago

The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a

Lunna [17]

Answer:

The change in power is 4400 W.

Explanation:

Given that,

Power = 10 kW

Speed = 10 m/s

Increases speed = 12 m/s

Given equation is,

$F=kv$

We know that,

The power is,

$P=Fv$

Put the value of F into the formula

$P=(kv)v$

$P=kv^2$

$P\propto v^2$

We need to calculate the new power

Using formula for power

$\dfrac{P}{P'}=\dfrac{v^2}{v'^2}$

Put the value into the formula

$\dfrac{10}{P'}=(\dfrac{10}{12})^2$

$P'=(\dfrac{12}{10})^2\times10$

$P'=14.4\ kW$

We need to calculate the change in power

Using formula of change in power

$\Delta P=P'-P$

Put the value into the formula

$\Delta P=14.4-10$

$\Delta P=4.4\ kW$

$\Delta P=4.4\times1000$

$\Delta P=4400\ W$

Hence, The change in power is 4400 W.

6 0

3 years ago

Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer

kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

$\lambda=\frac{b}{T}$

where

$\lambda$ is the peak wavelength

T is the surface temperature

$b=2.898\cdot 10^{-3} m\cdot K$ is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

$\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm$

Learn more about wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

8 0

2 years ago

8) A soccer goal is 2.44 m high. A player kicks the ball at a distance 10.0 m from the goal at an angle of 25.0°. The ball hits

White raven [17]

Answer:

The initial speed of the soccer ball is 16.38 m/s

Explanation:

given;

vertical distance y = 2.44 m

horizontal distance x = 10.0 m

angle of projection θ = 25.0°

Initial velocity has two components, Vₓ and V $_y$

Vₓ = V $_i$ cosθ

V $_y$ = V $_i$ sinθ

The horizontal distance = x = Vₓt + ¹/₂ ˣ g ˣ t², but g =0

x = Vₓt = V $_i$ cosθ *t

10 = V $_i$ cos25 *t

10 = 0.906V $_i$ *t

V $_i$ *t = 10/0.906 = 11.038 m

The vertical distance (g = - g, because it upward motion against gravity)

y = V $_y$ *t -¹/₂ ˣ g ˣ t²

2.44 = (V $_i$ sinθ)t - ¹/₂ ˣ 9.8 ˣ t²

2.44 = (V $_i$ *t)sinθ - ¹/₂ ˣ 9.8 ˣ t²

2.44 = (11.038)sin25° - 4.9t²

2.44 = (11.038)*0.4226 - 4.9t²

2.44 = 4.6647 - 4.9t²

4.9t² = 4.6647 - 2.44 = 2.2247

t² = 2.2247/4.9

t² = 0.454

t = √0.454

t = 0.674 s

Recall that V $_i$ *t = 11.038 m

V $_i$ *0.674 = 11.038 m, solve for V $_i$

V $_i$ = 11.038/0.674

V $_i$ = 16.38 m/s

Therefore, the initial speed of the soccer ball is 16.38 m/s

6 0

2 years ago

Another element is silvery-white with a shiny luster, is very brittle, and forms ions with a −2 charge. give one possible identi

Lesechka [4]

The element is magnesium ( Mg )

7 0

2 years ago

Read 2 more answers