Answer:
a)693.821N/m
b)17.5g
Explanation:
We the Period T we can find the constant k,
That is
squaring on both sides,
where,
M=hanging mass, m = spring mass,
k =spring constant
T =time period
a) So for the equation we can compare, that is,
the hanging mass M is x here, so comparing the equation we know that
b) In order to find the mass of the spring we make similar process, so comparing,
Answer:
H=1020.12m
Explanation:
From a balance of energy:
where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.
The relation between H and d is given by:
H = d*sin(30) Replace this into our previous equation:
From a sum of forces:
N -mg*cos(30) = 0 => N = mg*cos(30) Replacing this:
Now we can solve for d:
d = 2040.23m
Thus H = 1020.12m
ANSWER
EXPLANATION
Since the body is in equilibrium, total upward forces must equal total downward force.
Also the net horizontal forces acting on the body must be zero.
We need to resolve into vertical and horizontal components.
The horizontal component is
.
The vertical component is
.
Equating the up force to the downward forces gives,
.
This implies that,
.
Also the horizontal forces must be equal.
.
Dividing equation (1) by equation (2) gives,
.
.
Therefore the given angle that must make with the horizontal is approximately 35° to the nearest degree.
To solve the problem it is necessary to apply the concepts related to Conservation of linear Moment.
The expression that defines the linear momentum is expressed as
P=mv
Where,
m=mass
v= velocity
According to our data we have to
v=10m/s
d=0.05m
Volume
t = 3hours=10800s
From the given data we can calculate the volume of rain for 5 seconds
Where,
It is the period of time we want to calculate total rainfall, that is
Through water density we can now calculate the mass that fell during the 5 seconds:
Now applying the prevailing equation given we have to
Therefore the momentum of the rain that falls in five seconds is