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san4es73 [151]
2 years ago
10

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

ttached to the string and car instead of 2, then the applied force on the car will be
Physics
1 answer:
zysi [14]2 years ago
6 0

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

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A particle has a velocity of v→(t)=5.0ti^+t2j^−2.0t3k^m/s.
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a)a=5 i+2t j - 6\ t^2k

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a=5 i+2t j - 6\ t^2k

Therefore the acceleration function a will be

a=5 i+2t j - 6\ t^2k

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The magnitude of the acceleration will be

a=\sqrt{5^2+4^2+24^2}\ m/s^2

a= 24.83 m/s²

The direction of the acceleration a is given as

a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2

a)a=5 i+2t j - 6\ t^2k

b)a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2

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If the distance between us and a star is doubled, with everything else remaining the same, the luminosity Group of answer choice
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Answer:

remains the same, but the apparent brightness is decreased by a factor of four.

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A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

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The apparent brightness of a star is a measure of the rate at which radiated energy from a star reaches an observer on Earth per square meter per second.

The apparent brightness of a star is measured in watts per square meter.

If the distance between us (humans) and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of four (4).

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8 0
2 years ago
A rock is dropped from the top of a tall building. The rock's displacement in the last second before it hits the ground is 46 %
olasank [31]

Answer:

height is 69.68 m

Explanation:

given data

before it hits the ground =  46 % of entire distance

to find out

the height

solution

we know here acceleration and displacement that is

d = (0.5)gt²     ..............1

here d is distance and g is  acceleration and t is time

so when object falling it will be

h = 4.9 t²   ....................2

and in 1st part of question

we have (100% - 46% ) = 54 %

so falling objects will be there

0.54 h = 4.9 (t-1)²       ...................3

so

now we have 2 equation with unknown

we equate both equation

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substitute h in the second equation and find t

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t = 0.576 s and  3.771 s

we use here 3.771 s because  0.576 s is useless displacement in the last second before it hits the ground is 46 % of the entire distance it falls

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then h from equation 2

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h = 4.9 (3.771)²

h =  69.68 m

so height is 69.68 m

6 0
2 years ago
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