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san4es73 [151]
2 years ago
10

If each washer has a mass of 4.9 g, then the mass of two washers in kilograms would be Given that F = ma, and if 4 washers are a

ttached to the string and car instead of 2, then the applied force on the car will be
Physics
1 answer:
zysi [14]2 years ago
6 0

Given that,

Mass of each washer  = 4.9 g

We need to calculate the mass of two washers in kg

Using conversion of unit

Mass of each washer m= 4.9\times10^{-3}\ Kg

So, Mass of two washers is

M=2\times m

Put the value of m

M=2\times4.9\times10^{-3}\ k

M=0.0098\ Kg

If 4 washer are attached to the spring

We need to calculate the applied force on the car

Using formula of force

F=mg

Put the value into the formula

F=4\times4.9\times10^{-3}\times9.8

F=0.192\ N

Hence, (i), The mass of two washers is 0.0098 kg.

(ii). The applied force on the car is 0.192 N.

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Pls see attached file

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2 years ago
A tennis ball bounces on the floor three times. If each time it loses 22.0% of its energy due to heating, how high does it rise
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Answer:

H = 109.14 cm

Explanation:

given,                                                            

Assume ,                                                            

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                                                             = 0.78 unit

Balance after second collision = 0.78 ^2 unit

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Balance after third collision = 0.78 ^3 unit

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H be the height achieved after 3 collision

0.475 ( m g h) = m g H                  

H = 0.475 x h                                    

H = 0.475 x 2.3 m                          

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6 0
2 years ago
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19.99 kg m²/s

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r and  v are perpendicular to each other,

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l = 2.4 m

θ= 34°

g = 9.8 m/s²  and m = 5 kg

resolving using newtons second law in the vertical and horizontal components.

T cos θ − m g = 0

T sin θ − mw² lsin θ = 0

where T is the force with which the wire acts on the bob

w = √g / lcosθ

= √ 9.8 / 2.4 ×cos 34

= 2.2193 rad/s

the angular momentum  L = mr× v

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= 5 × 2.2193 (2.4 ×sin 34°)²

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8 0
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Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 20.0 m above water wit
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Answer:

Explanation:

Given that,

Height of the bridge is 20m

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The final speed at which the rock hits the water

Vf = 24.8 m/s

Using conservation of energy given by the question hint

Ki + Ui = Kf + Uf

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Ki + Ui = Kf + Uf

Where

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Ei = 308.5m J

Now,

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Ef = ½mVf² + m•g•hf

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3 0
2 years ago
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