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DanielleElmas [232]
1 year ago
13

A bullet starting from rest accelerates uniformly at a rate of 1,250 meters per square second. What is the bullet's speed after

it has traveled 100 meters?
Physics
1 answer:
Tatiana [17]1 year ago
8 0

Answer:

125,000

Explanation:

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If a 10 meter ramp helps you move a 500 kg object up 1 meter. What was the mechanical advantage of the ramp?
sattari [20]
The mechanical advantage of an inclined plane is

(Length of the incline) / (its height)

= (10m) / (1m)

= 10 .

It's the same for any load, and doesn't depend on the mass that you're trying to move up or down the ramp.
6 0
1 year ago
Honey bees can acquire a small net charge on the order of 1 pC as they fly through the air and interact with plants. Estimate th
Inessa [10]

Answer:

F = 2.01*10^-16N -^k

Explanation:

In order to calculate the magnetic force perceived by the bee, you use the following formula:

F=qv\ X\ B            (1)

q: charge of the bee = 1pC = 1*10^-12 C

The average speed of a bee and the magnetic field of the earth are:

v = 6.70m/s

B = 30*10^-6 T

The bee is flying to the west (-^i). You consider that the magnetic field direction is to the north (^j). Then, the direction of the magnetic force is:

-^i X ^j = -^k

You replace the values of the parameters in the equation (1), in order to calculate the magnitude of the force:

|F|=qvB=(1*10^{-12}C)(6.70m/s)(30*10^{-6}T)=2.01*10^{-16}N

The magnetic force perceived by the bee is 2.01*10^-16N in the -^k direction, that is, toward the ground

5 0
2 years ago
A stone with mass 0.80 kg is attached to one end of a string 0.90 m long. The string will break if its tension exceeds 60.0 N. T
AleksandrR [38]

Answer:

v=8.2158m/s

Explanation:

(a) Free-body diagram attached.

(b) The stone attached with the string experiences both centripetal (towards the center) and centrifugal (away from the center) forces. The tension of the string counters the centrifugal force until it breaks.

We know that,

Centrifugal force = \frac{mv^2}{r}

where,

m = mass of the stone

v = velocity of the stone

r = length of the string

To find the maximum speed attained by the stone without the string breaking, we must equate:

\frac{mv^2}{r} =60

or, v=\sqrt \frac{{r\times 60}}{m} } =\sqrt{\frac{0.90\times60}{0.80} } =8.2158m/s

5 0
1 year ago
What is the acceleration during the pushing-off phase, in m/27 Express your answer in meters per second squared. A bush baby, an
Sindrei [870]

Answer:

a = 12.78 g's

Explanation:

Height reached by the object after push off is given as

H = 2.3 m

v_f^2 - v_i^2 = 2 a s

now we have

0 - v^2 = 2(-9.81)(2.3)

v = 6.72 m/s

now we know that this push last for total distance of 0.18 m

so during the push we will have

v_f^2 - v_i^2 = 2 a d

6.72^2 - 0 = 2a(0.18)

a = 125.35 m/s^2

now in terms of g = 9.81 m/s/s we have

a = \frac{125.35}{9.81} gs

a = 12.78 g's

6 0
1 year ago
The molecule arrangement of ice, water and steam are very different. _______ has the most ordered arrangement, ______ has the ne
marysya [2.9K]

Answer:

do you still need an answer

Explanation:

because if you are i could give it to you

3 0
2 years ago
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