Answer:
The magnitude of the centripetal acceleration during the turn is 
Explanation:
Given :
Speed to the airplane in circular path , v = 115 m/s.
Time taken by plane to turn , t= 15 s.
Also , the plane turns from east to south i.e. quarter of a circle .
Therefore, time taken to complete whole circle is , 
Now , Velocity ,
Also , we know :
Centripetal acceleration ,
Putting all values we get :
Hence , this is the required solution .
Answer:
energy carried by the current is given by the pointyng vector
Explanation:
The current is defined by
i = dQ / dt
this is the number of charges per unit area over time.
The movement of the charge carriers (electrons) is governed by the applied potential difference, when the filament has a movement the drag speed of these moving electrons should change slightly.
But the energy carried by the current is given by the pointyng vector of the electromagnetic wave
S = 1 / μ₀ EX B
It moves at the speed of light and its speed depends on the properties of the doctor and is not disturbed by small changes in speed, therefore the current in the circuit does not change due to this movement
Refer to the diagram shown below.
When an athlete is in motion, he/she exerts a vertical force (the person's weight, W) on the ground. The ground exerts an equal and opposite force, N, the normal reaction on the athlete, so that W = N.
At the same time, the ground exerts a horizontal force, F, o n the athlete so that he/she does not slip.
The magnitude of the horizontal force is
F = μN = μW
where μ = the dynamic coefficient of friction.
Answer:
The horizontal force is μW,
where
W = the weight of the athlete and,
μ = the dynamic coefficient of friction.
Answer:
B. 1 m/s
Explanation:
Metric unit conversions:
0.3 km = 300m
5 minutes = 5*60 = 300 seconds
So if a seal can reach a depth of 300m in a time of 300 seconds, its diving speed is the distance divided by time duration
v = s/t = 300/300 = 1m/s
So B is the correct answer
To solve this problem, we use the formula:
I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]
I100 / I1 = 1 / 100^2
I100 / I1 = 10^-4
Therefore the change in intensity from 1m to 100m in decibels is:
B100 – B1 = 10 log(10^-4) dB = -40 dB
So the intensity at 100m is calculated as:
B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB
Answer:
100 dB
