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LenaWriter [7]
1 year ago
5

Why are fossil fuels considered nonrenewable resources if they are still forming beneath the surface today?

Physics
1 answer:
AleksandrR [38]1 year ago
7 0

B is the answer because it takes millions of years to form these fossil fuels and everyday we use way more than we can find we may have a surplus for now but we may run out sooner than some think

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Hey guys I really really need help with this question for ASAP! Explain what chart junk is and how it differs from the kind of i
Ahat [919]
I found a definition: Chartjunk<span> refers to all visual elements in </span>charts<span> and graphs that are not necessary to comprehend the information represented on the graph, or that distract the viewer from this information.</span>
3 0
2 years ago
Read 2 more answers
Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an
Igoryamba

Answer:

This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:

a=\frac{F}{m}

Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.

4 0
1 year ago
Three particles are moving perpendicular to a uniform magnetic field and travel on circular paths (see the drawing). They have t
Vaselesa [24]

Explanation:

Radius of a charged particle is given by

r=mv / Bq

= k/ q

where   k   =   m v / B         is a constant.

i.e.   more is the magnitude of  charge, less is the radius. (inversely proportional)

From the diagram  r_3   >   r_2   >   r_1  (more the curvature, less is the radius)

( although drawing is not given i am assuming the above order, however, one can change the order as per the diagram. The concept used remains the same)

therefore,    q_1   >   q_2   >   q_3 .

7 0
2 years ago
A nonuniform beam 4.50 m long and weighing 1.40 kN makes an angle of 25.0° below the horizontal. It is held in position by a fri
liubo4ka [24]

Answer:

T = 7.64 kN

F_y = 0.52 kN(Downwards)

F_x = 3.23 kN (Towards Left)

Explanation:

As we know that beam is in equilibrium

So here we can use torque balance as well as force balance for the beam

Now by torque balance equation at the pivot we can say

F(4.50 cos\theta) + mg(2cos\theta) = T \times 3

As we know that

mg = 1.40 kN

F = 5 kN

so we will have

5 kN(4.50 cos25) + 1.40 kN(2 cos25) = 3 T

T = 7.64 kN

Now force balance in vertical direction

F + mg = Tsin65 + F_y

5 + 1.40 = 7.64 sin65 + F_y

F_y = 0.52 kN(Downwards)

Force balance in horizontal direction

F_x = T cos65

F_x = 7.64 cos65

F_x = 3.23 kN (Towards Left)

7 0
2 years ago
A 100 cm3 block of lead weighs 11N is carefully submerged in water. One cm3 of water weighs 0.0098 N.
Pie

#1

Volume of lead = 100 cm^3

density of lead = 11.34 g/cm^3

mass of the lead piece = density * volume

m = 100 * 11.34 = 1134 g

m = 1.134 kg

so its weight in air will be given as

W = mg = 1.134* 9.8 = 11.11 N

now the buoyant force on the lead is given by

F_B = W - F_{net}

F_B = 11.11 - 11 = 0.11 N

now as we know that

F_B = \rho V g

0.11 = 1000* V * 9.8

so by solving it we got

V = 11.22 cm^3

(ii) this volume of water will weigh same as the buoyant force so it is 0.11 N

(iii) Buoyant force = 0.11 N

(iv)since the density of lead block is more than density of water so it will sink inside the water


#2

buoyant force on the lead block is balancing the weight of it

F_B = W

\rho V g = W

13* 10^3 * V * 9.8 = 11.11

V = 87.2 cm^3

(ii) So this volume of mercury will weigh same as buoyant force and since block is floating here inside mercury so it is same as its weight =  11.11 N

(iii) Buoyant force = 11.11 N

(iv) since the density of lead is less than the density of mercury so it will float inside mercury


#3

Yes, if object density is less than the density of liquid then it will float otherwise it will sink inside the liquid

3 0
1 year ago
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