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2 years ago

A bird flies at an average velocity of 3.60 m/s for 18.4 s. How far does it travel? (unit=m)

1 answer:

5 0

First, you have to write what you know:

V = 3.60 m/s
D = ?
T = 18.4 s

Next, you plug everything into this formula:

V = D/T
3.60 m/s = ?/18.4 s

Then, you multiply 3.60 m/s and 18.4 s

D = 66.24 m

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A 18.0−μF capacitor is placed across a 22.5−V battery for a few seconds and is then connected across a 12.0−mH inductor that has

Gelneren [198K]

Answer:

Part a)

$i = 10.4 mA$

Part b)

in this case the charge on the capacitor will become zero

Part c)

$t_1 = 0.73 ms$

Part d)

$t = 2.2 ms$

Explanation:

As we know that first capacitor is charged with the battery and then it is connected to the inductor

So here we will have

$Q = CV$

$Q = (18\mu F)(22.5 V)$

$Q = 405 \mu C$

Part a)

now since the total energy of capacitor is converted into the energy of inductor

so by energy conservation we can say

$\frac{Q^2}{2C} = \frac{1}{2}Li^2$

so maximum current is given as

$i = \sqrt{\frac{L}{C}}Q$

$i = \sqrt{\frac{12\times 10^{-3}}{18\times 10^{-6}}}(405\times 10^{-6})$

$i = 10.4 mA$

Part b)

When current is maximum then whole energy of capacitor is converted into magnetic energy of inductor

So in this case the charge on the capacitor will become zero

Part c)

Time period of oscillation of charge between the plates and inductor is given as

$T = 2\pi\sqrt{LC}$

$T = 2\pi\sqrt{(18\mu F)(12 mH)}$

$T = 2.92 ms$

now capacitor gets discharged first time after 1/4 of total time period

$t_1 = 0.73 ms$

Part d)

Since time period is T and capacitor gets discharged two times in one complete time period of the motion

so first it will discharges in T/4 time

then next T/4 it will get charged again

then next T/4 time it will again discharged

so total time taken

$t = 3T/4$

$t = 2.2 ms$

4 0

1 year ago

A coffee cup on the horizontal dashboard of a car slides forward when the driver decelerates from 45 kmh to rest in 3.5 s or les

Svetach [21]

Answer:

μs = 0.36

Explanation:

Assuming no other forces acting on the cup while the car is decelerating, the friction force is responsible for any horizontal movement of the cup.

If the cup is on the verge of starting to slide, the friction force can be expressed as follows:

Ff = -μs*N = -μs*m*g

This force produces a deceleration from 45 Kmh to rest, in 3.5 s or more.

Converting 45 kmh to m/s, we have:

$45 kmh *\frac{1000m}{1km} * \frac{1h}{3600 s} = 12.5 m/s$

We can find the acceleration, just applying the definition, with vf =0, as follows:

$a = \frac{-vf}{t} =\frac{-12.5m/s}{3.5s} = -3.57 m/s2$

According to Newton's 2nd law, we can write the following expression:

F = m*a = -μs*m*g

Simplifying common terms, we can solve for μs, as follows:

μs = $\frac{a}{-g} =\frac{-3.57 m/s2}{-9.80m/s2} = 0.36$

6 0

2 years ago

How and why does the distance between 2 electrodes affect the rate of electrolysis? ...?

Rasek [7]

<span>Nothing, in terms of the chemistry.

The distance between the electrodes affects the electrical resistance very slightly. Increasing the distance increases the resistance and reduces the current slightly, which reduces slightly the amount of product.

For most practical applications, for electrolysis done in a beaker, varying the distance between the electrodes will make little difference.

Increasing the concentration of the electrolyte will increase the current flow because there are more charged particles to carry charge, and increase the product yield.</span>

4 0

2 years ago

Kayla and her friends are setting up chairs for a school play each row will contain the same number of chairs Kayla knows that t

LUCKY_DIMON [66]

Answer:

96=8*c

Explanation:

4 0

1 year ago

A submarine periscope uses two totally reflecting 45-45-90 prisms with total internal reflection on the sides adjacent to the 45

Likurg_2 [28]

Answer

Given,

Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.

refractive index of water, n_a = 1.33

refractive index of glass, n_g = 1.52

When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.

7 0

1 year ago