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2 years ago

Suppose the value of one division of vernier scale is 0.5mm and the value of one main scale

Physics

1 answer:

gregori [183]2 years ago

8 0

Answer:

-0.01 mm

Explanation:

We are given that

The value of one division of vernier scale =0.5 mm

The value of one main scale division=0.49 mm

We have to find the value of least count of the instrument in mm.

We know that

Leas count of vernier caliper=1 main scale division-1 vernier scale division

Least count of vernier caliper=0.49-0.50=-0.01 mm

Hence, the least count of the instrument=-0.01 mm

Answer: -0.01 mm

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Explanation:

Initial time, t₁ = 2:30 pm

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Hence, this is the required solution.

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1 year ago

A mass is tied to a string and swung in a horizontal circle with a constant angular speed. show answer No Attempt If this speed

Liono4ka [1.6K]

Answer:

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Explanation:

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When v is doubled, the new force, $F_1$ , is

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Hence, the tension in the string is quadrupled.

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2 years ago

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valentinak56 [21]

Answer:

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E= $\frac{kQ}{r^2} r^$

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2 years ago

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For this problem:

wave length = (2/3)(length of string: 68 cm)
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2 years ago

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Rzqust [24]

D. Gravitational force.

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1 year ago

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