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zhenek [66]
2 years ago
11

The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one imp

ortant model is missing.
An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle.

Which atomic model is missing from this set?

Bohr’s model
Dalton’s model
Rutherford’s model
Thomson’s model

Physics
2 answers:
astraxan [27]2 years ago
8 0

Answer:

Daulton's model...  i took the test!

Explanation:

nexus9112 [7]2 years ago
4 0

Answer: Dalton’s model

Explanation:

In the attached image we can see four atomic models labeled with four letters:

W represents the current and accepeted atomic model: a nucleus with an electron cloud, where the orbit and position of the electrons around the nucleus is defined by specific regions (associated with specific energy levels) where there is a greater probability of finding the electron at any given moment. It is important to note this model was improved by the works in quantum physics done by Louis de Broglie and Erwin Schrodinger.

X represents Rutherford's model (This model was proposed after Thomson's model). Ernest Rutherford conducted a series of experiments in order to corroborate Thomson's atomic model. However the results of the experiment led him to find out there is a concentration of charge in the atom's core (which was later called nucleus) surrounded by electrons.  This lead to a new atomic model, in which the atom has a positive charged nucleus surrounded by negative charged particles that move similar to the orbit of the planet around the Sun.

Y represents Thomson's model, also called  the <em>plum pudding</em> model. This scientific found out that atoms contain small subatomic particles with a negative charge (later called electrons). However, taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons were immersed in the atom of positive charge that counteracted the negative charge of the electrons. Just like the raisins embedded in a pudding or bread.

Z represents Bohr's model. This model was proposed by the danish physicist Niels Bohr after Rutherford's model. In fact, this model was Rutherford's model with the following addition: electrons orbit the nucleus (like planets around the sun) in specific orbits at different energy levels around the nucleus.

So, the only missing model is <u>Dalton's model</u>, which was the first atomic model:  the atom represented as a solid, indestructible and indivisible mass. An idea that was already accepted by that time since the ancient Greeks.

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High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 43.7 m/s just before it strikes a 45
Helga [31]

Answer:

41.27m/s

Explanation:

According to law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the velocity after impact

Given

m1 = 0.2kg

u1 = 43.7m/s

m2 = 45.9g = 0.0459kg

u2 = 30.7m/s

Required

Velocity after impact v

Substitute the given parameters into the formula

0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v

8.74+1.409 = 0.2459v

10.149 = 0.2459v

v = 10.149/0.2459

v = 41.27m/s

Hence the speed of the golf ball immediately after impact is 41.27m/s

8 0
2 years ago
Large and small numbers are often best entered in exponential notation. For example, the mass of the earth is 5.98x1024 kg and t
Doss [256]

Answer:

The charge to mass ratio is -1.76\times10^{11}

Explanation:

Mass\ of\ electron=m_e=9.11\times10^{-31} kg\\ Charge\ of\ the\ electron=q_e=-1.60\times10^{-19} C\\

We need to find how much charge is contained  in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:

\frac{Charge\ of\ electron}{Mass\ of\ electron}=\frac{q_e}{m_e}\frac{C}{kg}=\frac{-1.60\times10^{-19} C}{9.11\times10^{-31} kg}=-1.76\times10^{11} \frac{C}{kg}

4 0
2 years ago
Read 2 more answers
One student did an experiment with sand, rocks, pebbles, and water. The steps of the experiment are shown below.
Lubov Fominskaja [6]
The intended observation in this experiment is to check the flow of water through the cotton cloth when pouring the water through different material (sand, rocks and pebbles).
We will observe that the rate of water flow changes depending on which material it is flowing through.
The used materials in this experiment (sand, rocks and pebbles) are the same as those forming different layers of the earth.

Therefore, based on the above explanation, we can infer that the best answer is:
<span>D. groundwater moves at different rates through different layers of the Earth</span>
3 0
2 years ago
Two spherical objects have masses of 200 kg and 500 kg. Their centers are separated by a distance of 25 m. Find the gravitationa
ElenaW [278]

Answer:

1.07 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 200kg

Mass 2  = 500kg

Distance of separation  = 25m

Unknown:

Gravitational attraction between the two bodies  = ?

Solution:

To solve this problem, we use the equation of the universal gravitation;

                 F  = \frac{G mass 1  x mass 2}{r^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹Nm²kg⁻²

r is the distance

 Now insert the parameters and solve;

    F  = \frac{6.67 x 10^{-11} x 200 x 500 }{25^{2} }   = 1.07 x 10⁻⁸N

8 0
1 year ago
ery large accelerations can injure the body, especially if they last for a considerable length of time. One model used to gauge
IgorC [24]

Answer:

2.98 second

Explanation:

The severity index is defined by :

S=a^{5/2}t

a is dimensionless constant that equals the number of multiples of g

Conditions are given as :

Initial velocity, u = 0

Acceleration, a = 34 m/s²

Final velocity, v = 16.4 km/h = 4.56 m/s

We can find t from the above data as follows :

t=\dfrac{v-u}{a}\\\\t=\dfrac{4.56-0}{34}\\\\t=0.134\ s

As a is the acceleration that is multiple of g.

So,

a=\dfrac{34}{9.8}=3.46

So,

Severity index,

S=a^{5/2}t\\\\S=(3.46)^{5/2}\times 0.134\\\\S=2.98\ s

Hence, the severity index for the collision is 2.98 seconds.

6 0
2 years ago
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