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andre [41]
2 years ago
12

A highly charged piece of metal (with uniform potential throughout) tends to spark at places where the radius of curvature is sm

all, or at places where there are sharp points. The breakdown electric field strength for air is about 3 106 V/m. (a) It is possible to calculate the maximum possible potential (relative to infinity) in air of a metal sphere of 18 cm radius. First, what is the maximum charge you can put on this sphere? C For that amount of charge, what is the potential of the sphere relative to infinity? volts (b) Next, calculate the maximum possible potential relative to infinity in air of a metal sphere of only 0.4 mm radius. What is the maximum charge you can put on this sphere? C For that amount of charge, what is the potential of the sphere relative to infinity? volts These results are related to the fact that if a piece of metal has a small radius of curvature, it will spark at relatively low potential relative to infinity.
Physics
1 answer:
k0ka [10]2 years ago
8 0

Answer:

look it up

Explanation:

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How are uniform circular motion maps the same as linear motion maps? Check all that apply.
Flauer [41]

Answer:

A: Time is represented by dots at 1-second intervals.

D: Velocity vectors change direction as the object’s direction changes.

Explanation:

3 0
2 years ago
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Superman is standing 393 m horizontally away from Lois Lane. A villain drops a rock from 4.00 m directly above Lois. If Superman
Sergio039 [100]

Answer:

-963.93 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 4=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{4\times 2}{9.81}}\\\Rightarrow t=0.903\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow 393=0\times 0.0903+\frac{1}{2}\times a\times 0.903^2\\\Rightarrow a=\frac{393\times 2}{0.903^2}\\\Rightarrow a=963.93\ m/s^2

The acceleration of Superman would be -963.93 m/s² from Lois' perspective

6 0
2 years ago
Which situation would create a field like the one shown here? A. an interaction between two magnetic south poles B. an interacti
alexgriva [62]

Answer:

you have no picture

Explanation:

if it shows the arrows going towards eachother it is north and south. if it is not it will be either north and north or south and south

4 0
2 years ago
Read 2 more answers
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
dlinn [17]

Answer:

a = 4.72 m/s²  

Explanation:

given,

mass of the box (m)= 6 Kg

angle of inclination (θ) = 39°

coefficient of kinetic friction (μ) = 0.19

magnitude of acceleration = ?

box is sliding downward so,

F - f = m a                        

f is the friction force

m g sinθ - μ N = ma                        

m g sinθ - μ m g cos θ = ma            

a = g sinθ - μ g cos θ                    

a = 9.8 x sin 39° - 0.19 x 9.8 x cos 39°

a = 4.72 m/s²                                      

the magnitude of acceleration of the box down the slope is a = 4.72 m/s²  

3 0
2 years ago
1) My 14V car battery could be used to charge my laptop, but I need to use an inverter to first convert it to a standard 120V. T
LenaWriter [7]

Answer:

1) Charge chord resistance is 75 Ω

2) Charge chord resistance is 6.33 Ω

Explanation:

1) To answer the question, we note that the the formula voltage is found as follows;

V = IR

Therefore,

R = \frac{V}{I} =  \frac{120}{1.6} = 75  \, \Omega

2) Where the voltage, V = 19.5 V and the current, I = 3.33 A, we have;

Initial resistance R₁ = 19.5 V/(3.33 A) = 5.86 Ω

However, to reduce the current to 1.6 A, we have;

R_T = \frac{19.5}{1.6} = 12.1875 \ \Omega

Therefore, where the resistance is found by the sum of the total resistance we have;

R_T = R₁ + Charge chord resistance

∴ 12.1875 = 5.86 + Charge chord resistance

Hence, charge chord resistance = 6.33 Ω

8 0
2 years ago
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