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andre [41]
2 years ago
12

A highly charged piece of metal (with uniform potential throughout) tends to spark at places where the radius of curvature is sm

all, or at places where there are sharp points. The breakdown electric field strength for air is about 3 106 V/m. (a) It is possible to calculate the maximum possible potential (relative to infinity) in air of a metal sphere of 18 cm radius. First, what is the maximum charge you can put on this sphere? C For that amount of charge, what is the potential of the sphere relative to infinity? volts (b) Next, calculate the maximum possible potential relative to infinity in air of a metal sphere of only 0.4 mm radius. What is the maximum charge you can put on this sphere? C For that amount of charge, what is the potential of the sphere relative to infinity? volts These results are related to the fact that if a piece of metal has a small radius of curvature, it will spark at relatively low potential relative to infinity.
Physics
1 answer:
k0ka [10]2 years ago
8 0

Answer:

look it up

Explanation:

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A container of nitrogen (an ideal diatomic gas, molecular weight=28) is at a pressure of 2 atm and has a mass density of 1.6 gra
Nikolay [14]

Answer:

Explanation:What is the root-mean-square velocity (vrms) of the center of mass of one of the molecules?

3 0
1 year ago
A two-resistor voltage divider employing a 2-k? and a 3-k? resistor is connected to a 5-V ground-referenced power supply to prov
vesna_86 [32]

Answer:

circuit sketched in first attached image.

Second attached image is for calculating the equivalent output resistance

Explanation:

For calculating the output voltage with regarding the first image.

Vout = Vin \frac{R_{2}}{R_{2}+R_{1}}

Vout = 5 \frac{2000}{5000}[/[tex][tex]Vout = 5 \frac{2000}{5000}\\Vout = 5 \frac{2}{5} = 2 V

For the calculus of the equivalent output resistance we apply thevenin, the voltage source is short and current sources are open circuit, resulting in the second image.

so.

R_{out} = R_{2} || R_{1}\\R_{out} = 2000||3000 = \frac{2000*3000}{2000+3000} = 1200

Taking into account the %5 tolerance, with the minimal bound for Voltage and resistance.  

if the -5% is applied to both resistors the Voltage is still 5V because the quotient  has 5% / 5% so it cancels. to be more logic it applies the 5% just to one resistor, the resistor in this case we choose 2k but the essential is to show that the resistors usually don't have the same value. applying to the 2k resistor we have:

Vout = 5 \frac{1900}{4900}\\Vout = 5 \frac{19}{49} = 1.93 V

Vout = 5 \frac{2100}{5100}\\Vout = 5 \frac{21}{51} = 2.05 V

R_{out} = R_{2} || R_{1}\\R_{out} = 1900||2850= \frac{1900*2850}{1900+2850} = 1140

R_{out} = R_{2} || R_{1}\\R_{out} = 2100||3150 = \frac{2100*3150 }{2100+3150 } = 1260

so.

V_{out} = {1.93,2.05}V\\R_{1} = {1900,2100}\\R_{2} = {2850,3150}\\R_{out} = {1140,1260}

4 0
2 years ago
A man holding 7N weight moves 7m horizontal and 5m vertical , find the work done
SashulF [63]

Answer:

35 J

Explanation:

The man is holding the box: this means that he is applying a force vertically upward, to balance the weight of the box (which pushes downward).

Therefore, we can ignore the horizontal displacement of the man, because the force applied (vertically upward) is perpendicular to that displacement (horizontal), so the work done for that is zero.

So, only the vertical motion contributes to the work. The work done by the man is equal to the gain in gravitational potential energy of the box, so:

W=(mg)\Delta h

where

mg=7 N is the weight of the box

\Delta h=5 m is the vertical displacement

Substituting, we find

W=(7N)(5 m)=35 J

8 0
2 years ago
An Object moving at a velocity of 30 m/s slows to a stop in 7 seconds. What was its acceleration
ollegr [7]

Answer:

<h3>The answer is 4.29 m/s²</h3>

Explanation:

The acceleration of an object given it's velocity and time taken acting on it can be found by using the formula

acceleration =  \frac{velocity}{time}  \\

From the question

velocity = 30 m/s

time = 7 s

We have

acceleration =  \frac{30}{7}  \\  = 4.285714...

We have the final answer as

<h3>4.29 m/s²</h3>

Hope this helps you

7 0
2 years ago
A hot piece of iron is thrown into the ocean and its temperature eventually stabilizes. Which of the following statements concer
777dan777 [17]

Answer:

E. The ocean gains more entropy than the iron loses.

Explanation:

When there is a spontaneous process , entropy of the system increases . Here hot iron is losing entropy and ocean is gaining entropy . Net effect will be gain of entropy . That means entropy gained by ocean is more than entropy lost by iron .

Hence option E is correct .

8 0
2 years ago
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