answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rosijanka [135]
2 years ago
5

Which situation would create a field like the one shown here? A. an interaction between two magnetic south poles B. an interacti

on between two magnetic north poles C. an interaction between a magnetic south pole and a north pole D. an interaction between a magnetic south pole and an aluminum bar E. an interaction between a magnetic north pole and a zinc bar
Physics
2 answers:
alexgriva [62]2 years ago
4 0

Answer:

you have no picture

Explanation:

if it shows the arrows going towards eachother it is north and south. if it is not it will be either north and north or south and south

andriy [413]2 years ago
3 0

Answer:

C. an interaction between a magnetic south pole and a north pole

Explanation:

  • According to the situation the magnetic properties of the fields of the south and the north by the nature of the electrically charged electromagnets. That exerts a force and likewise, the earth also has two magnetic poles that have positive and negative properties and both oppose the each other properties.
You might be interested in
The index of refraction of water is 1.33. If you (or a fish) were under calm water swimming in the daytime, looking upward you w
Zolol [24]

Answer:

Bbk

Explanation:

8 0
2 years ago
To eight significant figures, Avogadro's constant is 6.0221367×10^(23)mol−1. Which of the following choices demonstrates correct
Zepler [3.9K]

Answer with Explanation:

We are given Avogadro's constant =6.0221367\times 10^{23}mol^{-1}

There are eight significant figures.

We have to round off.

1.If we round off to four significant figures

The ten thousandth place of Avogadro's constant is less than five therefore, digits on left side of ten thousandth  place remains same and digits on right side of ten thousandth place and ten thousandth place  replace by zero.

 Then ,Avogadro's constant can be written as

6.022\times 10^{23}mol^{-1}

If we round off to 2 significant figures

Hundredth place of given number is less than 5 therefore, digits on left side of hundredth  place remains same and digits on right side of hundredth place and hundredth place replace by zero.

Then,Avogadro's constant can be written as

6.0\times 10^{23}mol^{-1}

If we round off six significant figures

6 is greater than 5 therefore, 1 will be added to 3 and digits on right side of 6 and 6 replace by zero and digits on left side of 6 remains same except 3.

Then, the Avogadro's constant can be written as

6.02214\times 10^{23}mol^{-1}

3 0
2 years ago
A very long line of charge with charge per unit length +8.00 μC/m is on the x-axis and its midpoint is at x = 0. A second very l
artcher [175]

Answer:

at y=6.29 cm the charge of the two distribution will be equal.

Explanation:

Given:

linear charge density on the x-axis, \lambda_1=8\times 10^{-6}\ C

linear charge density of the other charge distribution, \lambda_2=-6\times 10^{-6}\ C

Since both the linear charges are parallel and aligned by their centers hence we get the symmetric point along the y-axis where the electric fields will be equal.

Let the neural point be at x meters from the x-axis then the distance of that point from the y-axis will be (0.11-x) meters.

<u>we know, the electric field due to linear charge is given as:</u>

E=\frac{\lambda}{2\pi.r.\epsilon_0}

where:

\lambda= linear charge density

r = radial distance from the center of wire

\epsilon_0= permittivity of free space

Therefore,

E_1=E_2

\frac{\lambda_1}{2\pi.x.\epsilon_0}=\frac{\lambda_2}{2\pi.(0.11-x).\epsilon_0}

\frac{\lambda_1}{x} =\frac{\lambda_2}{0.11-x}

\frac{8\times 10^{-6}}{x} =\frac{6\times 10^{-6}}{0.11-x}

x=0.0629\ m

∴at y=6.29 cm the charge of the two distribution will be equal.

9 0
2 years ago
A car of mass 1100kg moves at 24 m/s. What is the braking force needed to bring the car to a halt in 2.0 seconds? N
LenaWriter [7]

13200N

Explanation:

Given parameters:

Mass = 1100kg

Velocity = 24m/s

time = 2s

unknown:

Braking force = ?

Solution:

The braking force is the force needed to stop the car from moving.

   Force  =  ma = \frac{mv}{t}

  m is the mass of the car

  v is the velocity

  t is the time taken

  Force = \frac{1100 x 24}{2} = 13200N

Learn more:

Force brainly.com/question/4033012

#learnwithBrainly

8 0
2 years ago
A car travels at a constant rate for 25 miles, going due east for one hour. Then it travels at a constant rate another 60 miles
egoroff_w [7]

60 mph east...........

6 0
2 years ago
Read 2 more answers
Other questions:
  • A rocket can fly into space because !
    7·1 answer
  • What is the total energy released when 9.11 x10^-31 ki?
    7·1 answer
  • The famous leaning tower of pisa doesn't topple over because its center of gravity is
    14·1 answer
  • A car with an initial velocity of 16.0 meters per second east slows uniformly to 6.0 meters per second east in 4.0 seconds. What
    8·1 answer
  • An electron is pushed into an electric field where it acquires a 1-v electrical potential. suppose instead that two electrons ar
    5·2 answers
  • Use the momentum equation for photons found in this week's notes, the wavelength you found in #3, and Plank’s constant (6.63E-34
    14·2 answers
  • A circular loop of wire is rotated at constant angular speed about an axis whose direction can be varied. In a region where a un
    7·1 answer
  • A floating leaf oscillates up and down two complete cycles in one second as a water wave passes by. The wave's wavelength is 10
    12·1 answer
  • Adam is teeing off on hole number two. The hole is 390 yards away. It is a par four hole. What club should he use to tee off? Ex
    5·1 answer
  • Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!