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makkiz [27]
1 year ago
13

A ball of mass 5.0kg is lifted off the floor a distance of 1.7m. 1. What is the change in the gravitational potential energy of

the ball? 2. Now you release the ball from rest, and it falls to the floor. What is the kinetic energy of the ball just before it hits the floor? 3. What is the velocity of ball just before it hits the floor?
Physics
1 answer:
tangare [24]1 year ago
4 0

Answer:

Explanation:

Change in gravitational energy of the ball = mgh

5 mutiply 10 multiply 1.7 = 85J

Potential energy at height = Kinetic energy at bottom

KE= 85J

Velocity

v=5.83m/s

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