Answer:
A 93%
Explanation:
= Pressure will be equal at inlet and outlet
= Density of water = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
= Velocity at inlet = 1.2 m/s
= Velocity at outlet
= Radius of inlet = 
= Radius of outlet
From Bernoulli's relation

From continuity equation

The fraction would be

The fraction is 93.0304%
The intensity is defined as the ratio between the power emitted by the source and the area through which the power is calculated:

(1)
where
P is the power
A is the area
In our problem, the intensity is

. At a distance of r=6.0 m from the source, the area intercepted by the radiation (which propagates in all directions) is equal to the area of a sphere of radius r, so:

And so if we re-arrange (1) we find the power emitted by the source:
Jogger moves in three displacements
d1 = 10 blocks East
d2 = 5 blocks South
d3 = 2 blocks East
now we can say
total displacement towards East direction will be

Total displacement towards South

now to find the net displacement we can use vector addition



<em>so magnitude of net displacement will be equal to 13 blocks</em>
Answer:
3.5 N
Explanation:
Let the 0-cm end be the moment point. We know that for the system to be balanced, the total moment about this point must be 0. Let's calculate the moment at each point, in order from 0 to 100cm
- Tension of the string attached at the 0cm end is 0 as moment arm is 0
- 2 N weight suspended from the 10 cm position: 2*10 = 20 Ncm clockwise
- 2 N weight suspended from the 50 cm position: 2*50 = 100 Ncm clockwise
- 1 N stick weight at its center of mass, which is 50 cm position, since the stick is uniform: 1*50 = 50 Ncm clockwise
- 3 N weight suspended from the 60 cm position: 3*60 = 180 Ncm clockwise
- Tension T (N) of the string attached at the 100-cm end: T*100 = 100T Ncm counter-clockwise.
Total Clockwise moment = 20 + 100 + 50 + 180 = 350Ncm
Total counter-clockwise moment = 100T
For this to balance, 100 T = 350
so T = 350 / 100 = 3.5 N