Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where =Angular frequency
A=Amplitude
Using the formula
Hence, the amplitude of oscillation=A=0.199
Answer:
(a) 2.8 V
(b) 5.6 V
(c) 9.8 V
Explanation:
Given:
Frequency of the generator (f) = 1300 Hz)
Terminal voltage (V) =12.0 V
Resistance of resistor (R) = 14.0 Ω
Capacitance of capacitor (C) = 4.40 μF = 4.40 × 10⁻⁶ F
Inductance of the inductor (L) = 6.00 mH = 6.00 × 10⁻³ H
In order to find the voltages across each, we first need to find the reactance and impedance.
Reactance of the inductor is given as:
Reactance of the capacitor is given as:
Now, impedance is given as:
Current across the circuit is given as:
As resistor, capacitor and inductor are connected in series, the current across each of them is same and equal to total current in the circuit.
(a)
Voltage across the resistor is given as:
Therefore, the voltage across resistor is 2.8 V.
(b)
Voltage across the capacitor is given as:
Therefore, the voltage across the capacitor is 5.6 V.
(c)
Voltage across the inductor is given as:
Therefore, the voltage across the inductor is 9.8 V.