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gulaghasi [49]
2 years ago
12

Alex is standing still and throws a football with a speed of 10 m/s to his friend, who is also standing still. The two friends a

re standing 5 meters apart. Which describes how each person observes the speed of the football?
Physics
2 answers:
Phantasy [73]2 years ago
7 0

The question is incomplete. It comes with a set of answer choices.


These are the answer choices:


Alex observes it as 10 m/s, and his friend observes it as less than 10 m/s.


Alex observes it as less than 10 m/s, and his friend observes it as 10 m/s.


Both Alex and his friend observe it as 10 m/s.


Both Alex and his friend observe it as less than 10 m/s.



Answer: Both Alex and his friend observe it as 10 m/s.


Justification:


1) The speed is relative to the frame of reference.


2) It is said that the both Alex and his friend are standing still.


3) Then, the speed they both see is the same, 10 m/s, respect the Earth (where they are standing still).


Of course, Alex is watching the ball moving away and his friend is seing it approaching, but it is not relevant for the question, as it deals with the speed which is only about magnitude, not direction.

Readme [11.4K]2 years ago
6 0

Answer:

c on edge

Explanation:

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zheka24 [161]

Answer:

Part A the answer is the dielectric constant.

Part B  Mica- mylar- paper- quartz

Explanation:

The capacity of a capacitor is given by

           C = ε ε₀ A / d

Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.

Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor

the flexibility of the material must also be taken into account

Part A the answer is the dielectric constant.

Pate B order the materials from best to worst

Mica. The best ever

Mylar Flexible

Paper Low capacity, low working voltage, flexible

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8 0
2 years ago
While dangling a hairdryer by its cord, you observe that the cord is vertical when the hairdryer isoff and, once it is turned on
jekas [21]

Answer:

The speed of the air leaving the hairdryer is 10m/s.

Explanation:

The thrust that the dryer produces is what keeps it elevated at an angle of 5° from the vertical; therefore, from the force diagram we get

(1).\: tan (5^o) = \dfrac{F_t}{Mg}

putting in M =0.420kg, g = 9.8m/s^2 and solving for F_t we get:

F_t = Mg\:tan(5^o)

F_t = (0.420kg)(9.8m/s^2)\:tan(5^o)

\boxed{F_t = 0.3601N.}

Now, this thrust produced is related to to the air ejection speed v by the relation

(2).\: F_t = v\dfrac{dM}{dt}

where dM/dt is the rate of air ejection which we know is

0.06m^3/2s  = 0.03m^3/s

and since 1m^3 = 1.2kg,

0.03m^3/s \rightarrow 0.036kg/s

\dfrac{dM}{dt}  = 0.036kg/s,

putting this into equation (2) and the value of F_t we get:

0.3601N = 0.036v

which gives

v= \dfrac{0.3601}{0.036}

\boxed{v =10m/s.}

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6 0
2 years ago
A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

8 0
2 years ago
An individual white LED (light-emitting diode) has an efficiency of 20% and uses 1.0 W of electric power. a. How many LEDs must
Neporo4naja [7]

Answer:

8, 8 W

Explanation:

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Total power required is 1.6 W

Number of Light Emitting Diodes would be

n=\dfrac{1.6}{0.2}\\\Rightarrow n=8

The number of Light Emitting Diodes is 8.

Power would be

P=8\times 1=8\ W

The power that is required to run the Light Emitting Diodes is 8 W

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ArbitrLikvidat [17]

D. Reduces the force of air resistance

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