Answer:
f=8.219*10^{8}Hz
Explanation:
We are going to use the formula v=fλ
Where v= velocity of radio waves
f= frequency
λ= wavelength of wave
- radio waves are electromagnetic waves and as such they have the speed of light which is 3*10^{8}m/s.
- also when a wave travels from one medium to another, the wavelength changes while the frequency remains the same.
- calculating for the frequency of the wave in air also gives us the frequency in the window glass.
f=\frac{v}{λ}
v=3*10^{8}m/s.
λ=36.5 cm = 36.5/100= 0.365m
f=\frac{3*10^{8}m/s.}{0.365m}
f=8.219*10^{8}Hz
Answer:
47.76°
Explanation:
Magnitude of dipole moment = 0.0243J/T
Magnetic Field = 57.5mT
kinetic energy = 0.458mJ
∇U = -∇K
Uf - Ui = -0.458mJ
Ui - Uf = 0.458mJ
(-μBcosθi) - (-μBcosθf) = 0.458mJ
rearranging the equation,
(μBcosθf) - (μBcosθi) = 0.458mJ
μB * (cosθf - cosθi) = 0.458mJ
θf is at 0° because the dipole moment is aligned with the magnetic field.
μB * (cos 0 - cos θi) = 0.458mJ
but cos 0 = 1
(0.0243 * 0.0575) (1 - cos θi) = 0.458*10⁻³
1 - cos θi = 0.458*10⁻³ / 1.397*10⁻³
1 - cos θi = 0.3278
collect like terms
cosθi = 0.6722
θ = cos⁻ 0.6722
θ = 47.76°
Answer:
aaaaa
Explanation:
M = Mass of the Earth
m = Mass of satellite
r = Radius of satellite
G = Gravitational constant




Answer:
3311N
Explanation:
r = radius = 600m
V = speed = 150m/s
Mass = weight = 70kg
The weight of pilot when calculated due to circular motion
W = tv
Fv = mv²/r
Fv = 70x150²/600
Fv = 79x22500/600
= 15750000/600
= 2625N
Real Weight of the pilot = m x g
= 70 x 9.8
= 686N
The apparent Weight is calculated by
Mv²/r + mg
= 2625N + 686N
= 3311 N
Therefore the apparent Weight is 3311N
There is no picture given so I can't be really sure what color of the cable you're referring to. However, the only relationship I can think of when the power and the current is given would be: P=IV or P = I²R, where P is power, I is current, V is voltage and R is resistance. Solving both equations:
120 W = (24 A)(Voltage)
Voltage = 5 V
120 W = (24 A)²(R)
R = 0.2083 Ω
So, i think the cable would have specification of 5 Volts and 0.2083 ohms.