
The ball is against the vector of gravity. Then, the gravity will be negative.

The ball will stop in the air after approx. 4.72 seconds. And will take the same time to hit the ground.
It will stay approx. 9.44 seconds in the air.
Answer:
a) V = 1.866 10² V
, b) V = 3.424 10⁵ V
, c) v = 8.1 10⁶ m / s
Explanation:
a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light
v = 0.027 c
v = 0.027 3 10⁸
v = 8.1 10⁶ m / s
for this part we can use the conservation of mechanical energy
starting point. When electrons are at rest
Em₀ = U = q V
final point. Electrons with maximum speed
Em_f = K = ½ m v2
Em₀ = Em_{f}
e V = ½ m v²
V = ½ m v² / e
let's calculate
V = ½ 9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 1.866 10² V
V = 1866 V
b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27
V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹
V = 3.424 10⁵ V
V = 342402 V
c)
this potential difference should give the protons the same speed as the electrons
v = 8.1 10⁶ m / s
Answer:
The cannonball fly horizontally before it strikes the ground, S = 323.25 m
Explanation:
Given data,
The height of the cliff, h = 80 m
The horizontal velocity of the cannonball, Vₓ = 80 m/s
The range of the cannon ball with initial vertical velocity is zero is given by the formula,


S = 323.25 m
Hence, the cannonball fly horizontally before it strikes the ground, S = 323.25 m
1 isla thanks for your help and I hope you are feeling 44356