Answer:
126.99115 g
Explanation:
50 g at 90 cm
Stick balances at 61.3 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)
The mass of the meter stick is 126.99115 g
-- Class I lever
The fulcrum is between the effort and the load.
The Mechanical Advantage can be anything, more or less than 1 .
Example: a see-saw
-- Class II lever
The load is between the fulcrum and the effort.
The Mechanical Advantage is always greater than 1 .
Example: a nut-cracker, a garlic press
-- Class III lever
The effort is between the fulcrum and the load.
The Mechanical Advantage is always less than 1 .
I can't think of an example right now.
In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object
according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is
total momentum before collision = total momentum after collision
P₁ + P₂ = P'₁ + P'₂
where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.
P'₁ - P₁ = - (P'₂ - P₂)
so clearly gain in momentum of one object is same as the loss of momentum of other object
We are given
the torque requirement of 97 Newton meter.
The formula of the torque is
τ = r * F * sinθ
where
τ is the torque
r = radius from the axis of rotation to the point of application.
F = force exerted
θ = the angle between the lever arm and the radius
Try to substitute the given and solve for F.
<h3>pressure = force / area</h3>
<h3>force = 84 N</h3><h3>pressure = 6 × 10 - 5 = 55 m2</h3>
<h3>pressure = 84 / 55</h3>
<h3>pressure = 1.53 pascals</h3>
hope that helps and please tell me if i am wrong :)
