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worty [1.4K]
1 year ago
9

Scenario A: 120 J of work is done in 6 s. Scenario B: 160 J of work is done in 8 s. Scenario C: 200 J of work is done in 10 s. W

hich scenario uses the most power?
Physics
2 answers:
hodyreva [135]1 year ago
8 0
Using the equation P = W/t to solve your problem . 

Thus the answer is all of them use the same amount of power. 20 J.  
Mice21 [21]1 year ago
6 0

Answer:

They all used the same power.

Explanation:

Power is equal to the ratio between the work done (W) and the time taken (t):

P=\frac{W}{t}

Let's calculate the power used in the three scenarios:

A) P=\frac{120 J}{6 s}=20 W

B) P=\frac{160 J}{8 s}=20 W

C) tex]P=\frac{200 J}{10 s}=20 W[/tex]

So, the power used is the same in the three scenarios.

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Which type of listening response includes the use of head nods, facial expressions, and short utterances such as "uh-huh" that s
BARSIC [14]
This type of listening response is called back-channel signal. This allows the speaker to know that the listener is attentive or willing to engage a conversation between them. It is shown through short utterances, facial expressions, head nods and others. 
4 0
2 years ago
16. A 7500 kg 18-wheeler traveling at 20 m/s exits onto the runaway truck ramp on the freeway.
miskamm [114]

Answer:

<em>765,000 Joule</em>

Explanation:

<u>Principle of Conservation of Energy </u>

The total energy in an isolated system cannot be created or destroyed, but transformed. Moving objects have kinetic energy, objects placed in some height above a reference level have gravitational potential energy. When they change their motion variables, one energy converts into the other, but if the numbers don't fit, we know there was some other type of energy acting into the system. The most common reason for energy 'losses' is the thermal energy, produced when objects move in rough surfaces or take friction from the air.

The 7,500 kg truck is originally traveling at 20 m/s to a certain height we'll set to 0. Thus, its total energy is  

\displaystyle E_1=\frac{mv^2}{2}

\displaystyle E_1=\frac{7,500\ 20^2}{2}

E_1=1,500,000\ Joule

When it comes to a stop, its speed is 0 and its height is 10 m higher than before. It means all the kinetic energy was transformed into other types of energy. The gravitational potential energy is

U=mgh=(7,500)(9.8)(10)=735,000\ Joule

Since this number is not equal to the previous value of the energy, the difference is due to thermal energy dissipated by friction

E_t=1,500,000\ Joule-735,000\ Joule=765,000\ Joule

7 0
2 years ago
A scuba diver has his lungs filled to half capacity (3 liters) when 10 m below the surface. If the diver holds his breath while
rjkz [21]

To solve this problem it is necessary to apply Boyle's law in which it is specified that

P_1V_1 =P_2 V_2

Where,

P_1 and V_1 are the initial pressure and volume values

P_2 and V_2 are the final pressure volume values

The final pressure here is the atmosphere, then

P_2 = 101325 \approx 1*10^5Pa

h = 10m

\rho_w = 1000kg/m^3

V_1 = 3.0L

Pressure at the water is given by,

P_1 = P_2 -\rho gh

P_1 = 1*10^5 +1000*9.8*10 =198000Pa

Using Boyle equation we have,

V_2 = \frac{P_1V_1}{P_2}

V_2 = \frac{198000*3*10^5}{10^5}

V_2 = 5.9L

Therefore the volume of the lungs at the surface is 5.9L

4 0
1 year ago
Mrs. Brown's class is studying magnets and electricity. At the end of the unit Claire states that magnets and electricity are bo
Gwar [14]

Answer:

Magnets can create electricity and electricity can create a magnetic force.

Both electric charges and magnets do not have to touch an object in order to exert a force on it.

Electromagnets use electricity to create a magnetic force.

Explanation:

7 0
2 years ago
Read 2 more answers
A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising th
kobusy [5.1K]

Answer:

24,267.6 watts

Explanation:

from the question we are given the following:

mass (m) = 810 kg

final velocity (v) = 7 m/s

initial velocity (u) = 0 m/s

time (t) = 3.5 s

final height (h₁) = 8.2 m

initial height (h₀) = 0 m

acceleration due to gravity (g) = 9.8 m/s^{2}

find the power

power = \frac{work done}[time}

and

work done = change in kinetic energy (K.E) + change in potential energy (P.E)

work done = (0.5 mv^{2} - 0.5 mu^{2} ) + ( mgh₁ - mgh₀)

since u and h₀ are zero the work done now becomes

work done = (0.5 mv^{2}) + ( mgh₁ )                    

work done = (0.5 x 810 x 7^{2}) + ( 810 x 9.8 x 8.2)

work done = 84, 936.6 joules

recall that power = \frac{work done}[time}

power = \frac{84,936.6}[3.5}

power = 24,267.6 watts

7 0
1 year ago
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