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Mariulka [41]
2 years ago
14

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction

between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 99 m/s. What vertical height does the puck reach above its starting point?
Physics
2 answers:
Vaselesa [24]2 years ago
6 0

Answer:

H=1020.12m

Explanation:

From a balance of energy:

\frac{m*Vo^2}{2} -mg*H=-Ff*d   where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.

The relation between H and d is given by:

H = d*sin(30)   Replace this into our previous equation:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*N*d

From a sum of forces:

N -mg*cos(30) = 0    =>  N = mg*cos(30)   Replacing this:

\frac{m*Vo^2}{2} -mg*d*sin(30)=-\mu_k*mg*cos(30)*d   Now we can solve for d:

d = 2040.23m

Thus H = 1020.12m

Black_prince [1.1K]2 years ago
5 0

Answer:

the vertical height reach by the puck is 329.06m

Explanation:

In all the process, the only non-conservative force presented in the problem is the frictional force. Therefore, applying the Mechanical energy conservation:

\Delta E_{M} =W_{ncf}

with:

E_{Mi}=\frac{1}{2} mv_{i} ^{2}\\E_{Mf}=mgH

W_{ncf}=\int\limits^L_0 {\vec{F_{roz}} } \,\cdot \vec{dx}=-|F_{roz}|L=-\frac{H|F_{roz}|}{sin(\alpha)}

From the dynamic analysis:

F_{roz}=\mu_{k}N=\mu_{k}cos(\alpha)mg

Therefore:

E_{Mf}-E_{Mi}=W_{ncf}

mgH-\frac{1}{2} mv_{i} ^{2}=-\frac{Hmg\mu_{k}}{tan(\alpha)}\\H-\frac{v_{i} ^{2}}{2g}=-\frac{H\mu_{k}}{tan(\alpha)}\\H(1+\frac{\mu_{k}}{tan(\alpha)})=\frac{v_{i} ^{2}}{2g}\\H=\frac{v_{i} ^{2}}{2g(1+\frac{\mu_{k}}{tan(\alpha)})}\\H=329.06m

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Elza [17]

Answer:

<h2>5.3 m</h2>

Explanation:

The standard film size for one popular camera was<u> 79 mm square</u>.

The film was <u>116 mm behind the lens</u>.

If you wanted a picture of your<u> 1.8-m-tall friend to fill half the frame</u>,

find:

how far away from you did she need to stand?

solution:

the other person called friend is 1.8 m tall (1,800mm) stood from the other side to fill up half of the frame of 79mm / 2 = 35 mm.

where the film behind the lens is 116mm as given.

so its a ratio and proportion:

<u>1800 mm </u> =  <u>     39.5 mm   </u>

     x                    116 mm

39.5 (x) = 1800 (116)

x =  <u> 208,800</u>

         39.5

x = 5286 mm * <u>      1  m     </u>

                          1000 mm

x = 5.3 m

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Metallic elements can exist on their own as individual atoms.

Nonmetals usually exist as molecules, combining with atoms of themselves.

Nonmetals can exist on their own as individual atoms.

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Non-metals like the noble gases exists on their own as individual atoms. They are mono-atomic gases and are stable in nature.

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