Answer:
e*P_s = 11 W
Explanation:
Given:
- e*P = 1.0 KW
- r_s = 9.5*r_e
- e is the efficiency of the panels
Find:
What power would the solar cell produce if the spacecraft were in orbit around Saturn
Solution:
- We use the relation between the intensity I and distance of light:
I_1 / I_2 = ( r_2 / r_1 ) ^2
- The intensity of sun light at Saturn's orbit can be expressed as:
I_s = I_e * ( r_e / r_s ) ^2
I_s = ( 1.0 KW / e*a) * ( 1 / 9.5 )^2
I_s = 11 W / e*a
- We know that P = I*a, hence we have:
P_s = I_s*a
P_s = 11 W / e
Hence, e*P_s = 11 W
It will be <span>Einstein's General Relativity</span>
<span>The answer of these two problems are :
A) a = (F-W)/m = (100-500)/500/g = 9.8*500/500 = +9.8
m/sec^2
B) a1 = +9.8-g = 0</span>
Answer:
Resistivity of both wires are same
Explanation:
Length of one wire,
Diameter,
Radius,




Temperature in each case is same.
Area of each wire,
Resistivity is the property of material due to which it offers resistance to the flow of current.
Resistivity of material depends upon the temperature and material by which it is made.
It does not depends upon the length of object.
Therefore, the resistivity of both wires of different length are same.
Answer:
times
Explanation:
First of all, we need to write both the age of the universe and the lifetime of the top quark in scientific notation.
Age of the universe:
(1 followed by 17 zeroes)
Lifetime of the top quark:
(we moved the decimal point 24 places to the right)
Therefore, to answer the question, we have to calculate the ratio between the age of the universe and the lifetime of the top quark:
