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Thepotemich [5.8K]
2 years ago
12

Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kg, is moving at 6.00 m/s to

the east just before the collision and at 3.00 m/s to the west just after the collision. Buffy, of mass 55.0 kg, is moving at 3.50 m/s to the east just after the collision. Find Buffy's velocity (magnitude and direction) just before the collision.
Physics
1 answer:
xeze [42]2 years ago
5 0

Explanation:

It is given that,

Mass of Madeleine, m_1=65\ kg

Initial speed of Madeleine, u_1=6\ m/s (due east)

Final speed of Madeleine, v_1=-3\ m/s (due west)

Mass of Buffy, m_2=55\ kg

Final speed of Buffy, v_2=3.5\ m/s (due east)

Let u_1 is the Buffy's velocity just before the collision. Using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

65\times 6+55\times u_2=65\times (-3)+55\times 3.5

u_2=-7.13\ m/s

So, the initial speed of the Buffy just before the collision is 7.13 m/s and it is moving due west. Hence, this is the required solution.

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Explanation:

Statement is incomplete. Complete description is presented below:

<em>A freight train has a mass of </em>1.83\times 10^{7}\,kg<em>. The wheels of the locomotive push back on the tracks with a constant net force of </em>7.50\times 10^{5}\,N<em>, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 kilometers per hour?</em>

If locomotive have a constant net force (F), measured in newtons, then acceleration (a), measured in meters per square second, must be constant and can be found by the following expression:

a = \frac{F}{m} (1)

Where m is the mass of the freight train, measured in kilograms.

If we know that F = 7.50\times 10^{5}\,N and m = 1.83\times 10^{7}\,kg, then the acceleration experimented by the train is:

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a = 4.098\times 10^{-2}\,\frac{m}{s^{2}}

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t = \frac{v-v_{o}}{a} (2)

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v - Final speed of the train, measured in meters per second.

v_{o} - Initial speed of the train, measured in meters per second.

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To solve this exercise it is necessary to apply the kinematic equations of angular motion.

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4)

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        KE_{10} = KE_{1f}  + KE_{2f}

  • So as kinetic energy is always positive, KEf₂ < KE₁₀.
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