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larisa86 [58]
1 year ago
14

Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react

ions in the table.
A 2-column table with 3 rows. The first column labeled reactants has entries 2 N a C l O subscript 3, 2 K C l O subscript 3, 2 L i C l O subscript 3. The second column labeled products has entries 2 N a C l + 3 O subscript 2, 3 O subscript 2 + 2 K C l, empty.

What products should she record in the last row of the table?
Physics
2 answers:
kipiarov [429]1 year ago
5 0

The products should she record in the last row of the table : <u>2LiCl + 3O₂</u>

<h3>Further explanation</h3>

There are several chemical reactions, namely:

  • Formation reaction
  • Decomposition reaction.
  • Replacement reaction.
  • Multiple replacement reactions
  • Neutralization reaction.
  • Combustion reaction.
  • Polymerization

The decomposition reaction in a chemical reaction shows the decomposition reaction of a compound into its constituent elements or compounds

Rosa recorded three similar decomposition reactions

Reactions that occur :

1. 2 NaClO₃ ⇒ 2NaCl + 3O₂

2. 2KClO₃ ⇒ 2KCl + 3O₂

3. 2LiClO₃  ⇒ 2LiCl + 3O₂

There are similarities in the decomposition that forms oxygen and chloride compounds

Learn more

homogenous mixture of two or more pure substances

brainly.com/question/1832352

Keywords : products, patterns, chemical reaction, table, decomposition reactions

#LearnWithBrainly

boyakko [2]1 year ago
4 0

Answer:

2LiCl + 3O₂

Explanation:

Hopefully this helps

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rjkz [21]

Answer:

The stars are moving away from us.

Explanation:

The observed wavelengths of hydrogen transition for stars A and B (660.0 nm and 666 nm respectively) are greater than that observed in the laboratory (656.2 nm). The observed long wavelengths for the stars means that the light from the stars is red-shifted.

According to the Doppler effect, red-shifted light means that the source is moving a way from the observer; therefore, we arrive at the conclusion that the stars A and B are moving away from us.

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Table 2.4 shows how the dispacement of a runner changed during a sprint race. Draw a dispacement-time graph to show this data, a
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4. Table 2.4 shows how the displacement of a runner changed
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Displacement
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0 4 10 20 50 80 105
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A shift in one fringe in the Michelson-Morley experiment corresponds to a change in the round-trip travel time along one arm of
olya-2409 [2.1K]

Explanation:

When Michelson-Morley apparatus is turned through 90^{o} then position of two mirrors will be changed. The resultant path difference will be as follows.

      \frac{lv^{2}}{\lambda c^{2}} - (-\frac{lv^{2}}{\lambda c^{2}}) = \frac{2lv^{2}}{\lambda c^{2}}

Formula for change in fringe shift is as follows.

          n = \frac{2lv^{2}}{\lambda c^{2}}

       v^{2} = \frac{n \lambda c^{2}}{2l}

             v = \sqrt{\frac{n \lambda c^{2}}{2l}}

According to the given data change in fringe is n = 1. The data is Michelson and Morley experiment is as follows.

             l = 11 m

    \lambda = 5.9 \times 10^{-7} m

           c = 3.0 \times 10^{8} m/s

Hence, putting the given values into the above formula as follows.

            v = \sqrt{\frac{n \lambda c^{2}}{2l}}

               = \sqrt{\frac{1 \times (5.9 \times 10^{-7} m) \times (3.0 \times 10^{8})^{2}}{2 \times 11 m}}

               = 2.41363 \times 10^{9} m/s

Thus, we can conclude that velocity deduced is 2.41363 \times 10^{9} m/s.

3 0
1 year ago
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweez
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(a)  3.3\cdot 10^{-6} Pa

The radiation pressure exerted by an electromagnetic wave on a surface that totally absorbs the radiation is given by

p=\frac{I}{c}

where

I is the intensity of the wave

c is the speed of light

In this problem,

I=1000 W/m^2

and substituting c=3\cdot 10^8 m/s, we find the radiation pressure

p=\frac{1000 W/m^2}{3\cdot 10^8 m/s}=3.3\cdot 10^{-6}Pa

(b) 4.4\cdot 10^{-8} m/s^2

Since we know the cross-sectional area of the laser beam:

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starting from the radiation pressure found at point (a), we can calculate the force exerted on a tritium atom:

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And then, since we know the mass of the atom

m=5.01\cdot 10^{-27}kg

we can find the acceleration, by using Newton's second law:

a=\frac{F}{m}=\frac{2.2\cdot 10^{-34} N}{5.01\cdot 10^{-27} kg}=4.4\cdot 10^{-8} m/s^2

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The bus and the truck have the same velocity.

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